De Broglie's Relationship NEET Questions

De Broglie's Relationship MCQ Questions

7.
Two particles, X and Y, have the same kinetic energy, but the mass of X is greater than the mass of Y. Which particle has the longer de Broglie wavelength?
A.
Particle X
B.
Both have equal wavelength
C.
Cannot be determined without knowing charge
D.
Particle Y
ANSWER :
D. Particle Y
8.
An electron and a proton are moving with the same kinetic energy. Which particle has a longer de Broglie wavelength, and why?
A.
Electron, because its mass is much smaller
B.
Proton, because it moves faster
C.
Both have equal wavelength, as energy is the same
D.
Proton, because it has a positive charge
ANSWER :
A. Electron, because its mass is much smaller
9.
According to de Broglie, a stationary electron (v = 0) will have what associated wavelength?
A.
A fixed wavelength equal to h
B.
Infinite wavelength
C.
Zero wavelength
D.
A wavelength equal to Planck's constant divided by mass
ANSWER :
B. Infinite wavelength
10.
Why is the wave nature of macroscopic objects such as a cricket ball not observed in everyday life?
A.
Planck's constant is different for large objects
B.
Macroscopic objects have no momentum
C.
Their mass is so large that the associated de Broglie wavelength becomes negligibly small
D.
Macroscopic objects do not obey the laws of quantum mechanics
ANSWER :
C. Their mass is so large that the associated de Broglie wavelength becomes negligibly small
11.
The de Broglie equation was derived by combining Planck's quantum theory of radiation with which other concept?
A.
Bohr's quantization of angular momentum
B.
Einstein's mass–energy relationship (E = mc²)
C.
Heisenberg's uncertainty principle
D.
Rutherford's nuclear model
ANSWER :
B. Einstein's mass–energy relationship (E = mc²)
12.
Which experiment provided the first direct experimental confirmation of the wave nature of electrons, as predicted by de Broglie?
A.
Davisson–Germer electron diffraction experiment
B.
Millikan's oil drop experiment
C.
Rutherford's gold foil experiment
D.
Photoelectric effect experiment
ANSWER :
A. Davisson–Germer electron diffraction experiment