Tetravalency of Carbon: Shapes of Simple Molecules NEET Questions

Tetravalency of Carbon: Shapes of Simple Molecules MCQ Questions

7.
In ethene molecule (C₂H₄), all six atoms lie in the same plane because:
A.
There is restricted rotation about C=C double bond and parallel p-orbitals must overlap sideways
B.
Carbon atoms are sp³ hybridised
C.
Free rotation about C=C is allowed
D.
There is no π bond present
ANSWER :
A. There is restricted rotation about C=C double bond and parallel p-orbitals must overlap sideways
8.
Which of the following statements is INCORRECT regarding π bonds?
A.
π bonds are formed by sideways overlap of p-orbitals
B.
π bonds provide reactive centres in molecules
C.
π electron cloud lies above and below the plane of bonding atoms
D.
π bonds are stronger than σ bonds
ANSWER :
D. π bonds are stronger than σ bonds
9.
The hybridisation of each carbon atom in benzene (C₆H₆) is:
A.
sp³d
B.
sp
C.
sp²
D.
sp³
ANSWER :
C. sp²
10.
The C–H bond length is shortest in:
A.
C₂H₂
B.
CH₄
C.
C₂H₆
D.
C₂H₄
ANSWER :
A. C₂H₂
11.
Which carbon atom is most electronegative?
A.
sp² carbon
B.
sp carbon
C.
sp³ carbon
D.
sp³d carbon
ANSWER :
B. sp carbon
12.
The hybridisation states of carbon atoms in (CH₃)₂CO (acetone) are:
A.
sp, sp²
B.
sp², sp²
C.
sp³, sp³
D.
sp³, sp²
ANSWER :
D. sp³, sp²