Ionic Bonding (Formation of Ionic Bonds, Factors Affecting the Formation of Ionic Bonds; Calculation of Lattice Enthalpy ) NEET Questions

Physical Chemistry - Chemical Bonding and Molecular Structure

Ionic Bonding (Formation of Ionic Bonds, Factors Affecting the Formation of Ionic Bonds; Calculation of Lattice Enthalpy ) MCQ Questions


1.
Which of the following is the most essential condition for the formation of an ionic bond between two atoms?
A.
One atom should have low ionization enthalpy and the other should have high negative electron gain enthalpy
B.
Both atoms should be of similar size
C.
Both atoms should have high ionization enthalpies
D.
Both atoms should have high electron gain enthalpies
😑 View Answer Rough Work Error
ANSWER :
A. One atom should have low ionization enthalpy and the other should have high negative electron gain enthalpy
2.
The lattice enthalpy of NaCl is 788 kJ/mol. This represents the energy:
A.
Released when 1 mole of NaCl is formed from Na⁺(g) and Cl⁻(g)
B.
Required to separate 1 mole of solid NaCl into Na⁺(g) and Cl⁻(g)
C.
Released during the formation of NaCl(s) from Na(s) and Cl₂(g)
D.
Required to convert 1 mole of NaCl(s) into Na(g) and Cl(g)
😑 View Answer Rough Work Error
ANSWER :
B. Required to separate 1 mole of solid NaCl into Na⁺(g) and Cl⁻(g)
3.
In the formation of NaCl from Na(s) and Cl₂(g), the ionization enthalpy of Na is 495.8 kJ/mol and electron gain enthalpy of Cl is -348.7 kJ/mol. The lattice enthalpy of NaCl is -788 kJ/mol. The net energy change for these three steps combined is approximately:
A.
-641.5 kJ/mol
B.
+641.5 kJ/mol
C.
-147.1 kJ/mol
D.
+147.1 kJ/mol
😑 View Answer Rough Work Error
ANSWER :
A. -641.5 kJ/mol
4.
Which of the following pairs of elements is most likely to form an ionic bond?
A.
H and Cl
B.
N and H
C.
Cs and F
D.
C and O
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ANSWER :
C. Cs and F
5.
The formation of CaF₂ from Ca and F atoms involves which of the following correct sequence?
A.
Ca + 2F → CaF₂ directly without ion formation
B.
Ca → Ca⁺ + e⁻ ; F + e⁻ → F⁻ ; Ca⁺ + F⁻ → CaF
C.
Ca → Ca²⁺ + 2e⁻ ; F + e⁻ → F⁻ ; Ca²⁺ + 2F⁻ → CaF₂
D.
Ca → Ca²⁻ + 2e⁻ ; F → F⁺ + e⁻ ; Ca²⁻ + 2F⁺ → CaF₂
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ANSWER :
C. Ca → Ca²⁺ + 2e⁻ ; F + e⁻ → F⁻ ; Ca²⁺ + 2F⁻ → CaF₂
6.
Which of the following statements about lattice enthalpy is INCORRECT?
A.
Higher lattice enthalpy means greater stability of the ionic compound
B.
Lattice enthalpy can be calculated directly from Coulomb's law for any 3D crystal
C.
Lattice enthalpy decreases with increase in size of the ions
D.
Lattice enthalpy increases with increase in charge on the ions
😑 View Answer Rough Work Error
ANSWER :
B. Lattice enthalpy can be calculated directly from Coulomb's law for any 3D crystal