Equilibrium Involving Chemical Processes (Law of Chemical Equilibrium, Equilibrium Constants,...) NEET Questions

Physical Chemistry - Equilibrium
Equilibrium Involving Chemical Processes (Law of Chemical Equilibrium, Equilibrium Constants,...)

Equilibrium Involving Chemical Processes (Law of Chemical Equilibrium, Equilibrium Constants,...) MCQ Questions


13.
For which reaction is Kp = Kc?
A.
2NO2(g) โ‡Œ N2O4(g)
B.
PCl5(g) โ‡Œ PCl3(g) + Cl2(g)
C.
H2(g) + I2(g) โ‡Œ 2HI(g)
D.
N2(g) + 3H2(g) โ‡Œ 2NH3(g)
๐Ÿ˜‘ View Answer Error
ANSWER :
C. H2(g) + I2(g) โ‡Œ 2HI(g)
14.
For the reaction N2(g) + 3H2(g) โ‡Œ 2NH3(g), the relation between Kp and Kc is:
A.
Kp = Kc
B.
Kp = Kc(RT)โปยฒ
C.
Kp = Kc(RT)
D.
Kp = Kc(RT)ยฒ
๐Ÿ˜‘ View Answer Error
ANSWER :
B. Kp = Kc(RT)โปยฒ
15.
For 2NOCl(g) โ‡Œ 2NO(g) + Cl2(g), Kc = 3.75 ร— 10โปโถ at 1069 K. The value of Kp is approximately (R = 0.0831 bar L/mol K):
A.
1.0
B.
0.083
C.
3.75 ร— 10โปโถ
D.
0.033
๐Ÿ˜‘ View Answer Error
ANSWER :
D. 0.033
16.
In the expression Kp = Kc(RT)^ฮ”n, R has units of:
A.
J/mol K
B.
bar L/mol K (= 0.0831)
C.
atm/K
D.
Paยทmยณ
๐Ÿ˜‘ View Answer Error
ANSWER :
B. bar L/mol K (= 0.0831)
17.
For the reaction PCl5(g) โ‡Œ PCl3(g) + Cl2(g), Kc = 1.79 at 500 K. The relation between Kp and Kc is:
A.
Kp = Kc/(RT)
B.
Kp = Kc(RT)ยฒ
C.
Kp = Kc(RT)
D.
Kp = Kc
๐Ÿ˜‘ View Answer Error
ANSWER :
C. Kp = Kc(RT)
18.
Which of the following is a heterogeneous equilibrium?
A.
H2(g) + I2(g) โ‡Œ 2HI(g)
B.
N2(g) + 3H2(g) โ‡Œ 2NH3(g)
C.
2SO2(g) + O2(g) โ‡Œ 2SO3(g)
D.
CaCO3(s) โ‡Œ CaO(s) + CO2(g)
๐Ÿ˜‘ View Answer Error
ANSWER :
D. CaCO3(s) โ‡Œ CaO(s) + CO2(g)
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