Total Internal Reflection and its Applications NEET Questions

Total Internal Reflection and its Applications MCQ Questions

1.
Total internal reflection (TIR) occurs when light:
A.
Travels from a rarer medium to a denser medium at any angle
B.
Travels from a denser medium to a rarer medium and the angle of incidence exceeds the critical angle
C.
Strikes any surface at an angle of 90°
D.
Passes between two media of equal refractive indices
ANSWER :
B. Travels from a denser medium to a rarer medium and the angle of incidence exceeds the critical angle
2.
The critical angle for a pair of media is defined as:
A.
The angle of refraction equal to the angle of incidence
B.
The angle of incidence at which all light is refracted
C.
The angle of incidence (in the denser medium) for which the angle of refraction in the rarer medium is 90°
D.
The angle at which Brewster's law is satisfied
ANSWER :
C. The angle of incidence (in the denser medium) for which the angle of refraction in the rarer medium is 90°
3.
The two essential conditions for total internal reflection are:
A.
Light must travel from denser to rarer medium AND angle of incidence must exceed critical angle
B.
Light must be monochromatic AND incident at 45°
C.
The reflecting surface must be smooth AND polished
D.
The two media must be transparent AND have equal densities
ANSWER :
A. Light must travel from denser to rarer medium AND angle of incidence must exceed critical angle
4.
When the angle of incidence equals the critical angle, the angle of refraction is:
A.
90° (refracted ray grazes the surface)
B.
180°
C.
Equal to the angle of incidence
D.
0° (along the normal)
ANSWER :
A. 90° (refracted ray grazes the surface)
5.
The relation between critical angle (i_c) and refractive index (n) of the denser medium with respect to the rarer is:
A.
sin(i_c) = 1/n
B.
cos(i_c) = 1/n
C.
sin(i_c) = n
D.
tan(i_c) = 1/n
ANSWER :
A. sin(i_c) = 1/n
6.
The refractive index of denser medium (1) with respect to rarer medium (2) in terms of critical angle is:
A.
n₁₂ = tan(i_c)
B.
n₁₂ = 1/sin(i_c)
C.
n₁₂ = sin(i_c)
D.
n₁₂ = cos(i_c)
ANSWER :
B. n₁₂ = 1/sin(i_c)