Simple Pendulum - Derivation of Expression for its Time Period NEET Questions

Simple Pendulum - Derivation of Expression for its Time Period MCQ Questions

1.
In a simple pendulum, the 'bob' refers to:
A.
The string itself
B.
A small, heavy mass tied to an inextensible string
C.
The pivot point of the pendulum
D.
The rigid support from which the string is hung
ANSWER :
B. A small, heavy mass tied to an inextensible string
2.
Which assumption is essential to treat a simple pendulum as a 'simple' pendulum?
A.
The string must be made of metal
B.
The string must be horizontal at rest
C.
The bob must be hollow
D.
The string is massless and inextensible, and the bob is a point mass
ANSWER :
D. The string is massless and inextensible, and the bob is a point mass
3.
In the free-body diagram of a simple pendulum bob at angular displacement θ, the two forces acting on the bob are:
A.
Tension T along the string (upward along string) and weight mg vertically downward
B.
Normal reaction and weight
C.
Centripetal force and tension
D.
Tension T horizontally and weight mg vertically
ANSWER :
A. Tension T along the string (upward along string) and weight mg vertically downward
4.
The weight mg of the pendulum bob is resolved into two components. These are:
A.
mg along horizontal and mg along vertical
B.
mg cosθ along the string (radial) and mg sinθ perpendicular to the string (tangential)
C.
mg/2 along string and mg/2 tangentially
D.
mg sinθ along the string and mg cosθ perpendicular
ANSWER :
B. mg cosθ along the string (radial) and mg sinθ perpendicular to the string (tangential)
5.
In the derivation of the pendulum's time period, why is torque about the support point preferred over direct force analysis?
A.
Because force analysis is more complex in circular motion
B.
Because the radial force (tension and mg cosθ) gives zero torque, leaving only the tangential restoring torque
C.
Because torque gives a larger numerical value
D.
Because the string tension is unknown
ANSWER :
B. Because the radial force (tension and mg cosθ) gives zero torque, leaving only the tangential restoring torque
6.
The restoring torque on a pendulum bob displaced by angle θ from vertical is:
A.
τ = −mgL sinθ
B.
τ = mgL cosθ
C.
Ï„ = mgL
D.
τ = −mgL tanθ
ANSWER :
A. τ = −mgL sinθ