Vapour Pressure - Composition, Plots for Ideal and Non-Ideal Solutions NEET Questions

Physical Chemistry - Solutions

Vapour Pressure - Composition, Plots for Ideal and Non-Ideal Solutions MCQ Questions


7.
At x₁ = 1 in a binary solution of liquids 1 and 2, the total vapour pressure equals:
A.
p₂° (vapour pressure of pure component 2)
B.
Zero
C.
Sum of p₁° and p₂°
D.
p₁° (vapour pressure of pure component 1)
😑 View Answer Rough Work Error
ANSWER :
D. p₁° (vapour pressure of pure component 1)
8.
If the vapour pressures of pure components 1 and 2 are p₁° = 200 mm Hg and p₂° = 400 mm Hg, the total vapour pressure of an ideal solution at x₂ = 0.5 is:
A.
300 mm Hg
B.
600 mm Hg
C.
400 mm Hg
D.
200 mm Hg
😑 View Answer Rough Work Error
ANSWER :
A. 300 mm Hg
9.
For an ideal solution where component 2 is more volatile (p₂° > p₁°), as x₂ increases from 0 to 1, the total vapour pressure:
A.
Remains constant
B.
Decreases linearly from p₂° to p₁°
C.
Shows a maximum in the middle
D.
Increases linearly from p₁° to p₂°
😑 View Answer Rough Work Error
ANSWER :
D. Increases linearly from p₁° to p₂°
10.
Which equation correctly relates the total vapour pressure of an ideal binary solution to the mole fraction of component 2 only?
A.
p_total = p₁° − (p₂° − p₁°)x₂
B.
p_total = p₁°x₂ + p₂°x₁
C.
p_total = p₁° + (p₂° − p₁°)x₂
D.
p_total = p₂° + (p₁° − p₂°)x₂
😑 View Answer Rough Work Error
ANSWER :
C. p_total = p₁° + (p₂° − p₁°)x₂
11.
In a binary ideal solution, the mole fraction of component 1 in the vapour phase (y₁) is given by:
A.
y₁ = p_total/p₁
B.
y₁ = x₁ × p_total
C.
y₁ = p₁/p_total
D.
y₁ = p₁ × p_total
😑 View Answer Rough Work Error
ANSWER :
C. y₁ = p₁/p_total
12.
For an ideal binary solution at equilibrium, the vapour phase is always richer in:
A.
Both components equally
B.
The less volatile component
C.
The component with larger mole fraction in liquid
D.
The more volatile component
😑 View Answer Rough Work Error
ANSWER :
D. The more volatile component