Coulomb’s Law (Forces Between Two Point Charges, Forces Between Multiple Charges... ) NEET Questions

Physics - Electrostatics
Coulomb’s Law (Forces Between Two Point Charges, Forces Between Multiple Charges... )

Coulomb’s Law (Forces Between Two Point Charges, Forces Between Multiple Charges... ) MCQ Questions


13.
Both Coulomb's law (electric) and Newton's law of gravitation have inverse-square distance dependence. A key difference is:
A.
Gravitational force obeys superposition; Coulomb force does not
B.
Gravitational force is always attractive; Coulomb force can be both attractive (unlike charges) and repulsive (like charges) — this allows partial or complete cancellation of electric forces
C.
Gravitational force is stronger than Coulomb force at large distances
D.
Coulomb force has infinite range; gravitational force has finite range
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ANSWER :
B. Gravitational force is always attractive; Coulomb force can be both attractive (unlike charges) and repulsive (like charges) — this allows partial or complete cancellation of electric forces
14.
The acceleration of an electron placed 1 Å (= 10⁻¹⁰ m) from a proton due to their mutual Coulomb attraction is approximately:
A.
aₑ ≈ 1.4 × 10¹⁹ m/s²
B.
aₑ ≈ 2.5 × 10¹² m/s²
C.
aₑ ≈ 9.8 m/s² — equal to gravitational acceleration
D.
aₑ ≈ 2.5 × 10²² m/s² — vastly larger than g = 9.8 m/s², so gravity is negligible
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ANSWER :
D. aₑ ≈ 2.5 × 10²² m/s² — vastly larger than g = 9.8 m/s², so gravity is negligible
15.
If the distance between two point charges is doubled (charges unchanged), the Coulomb force becomes:
A.
F/4 — force decreases to one-quarter of original (inverse square law)
B.
F/2 — force halves
C.
4F — force quadruples
D.
2F — force doubles
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ANSWER :
A. F/4 — force decreases to one-quarter of original (inverse square law)
16.
If the distance between two charges is halved and each charge is doubled, the new Coulomb force compared to the original is:
A.
4F
B.
16F — force increases 16-fold
C.
8F
D.
2F
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ANSWER :
B. 16F — force increases 16-fold
17.

The electrostatic force between two charges is 0.2 N when separated by some distance r. When the separation is increased by 50% (to 1.5r), the force becomes:

A.

F' = 0.2 × (1.5)² = 0.45 N

B.

F' = 0.2/1.5 ≈ 0.133 N

C.

F' = 0.2/(1.5)² ≈ 0.089 N 

D.

F' = 0.2 × 1.5 = 0.3 N

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ANSWER :

C. F' = 0.2/(1.5)² ≈ 0.089 N 

18.
A small charged sphere of charge 0.4 μC is placed in air near another sphere of charge −0.8 μC. The force between them is 0.2 N. The distance between them is:
A.
r = 0.12 m = 12 cm
B.
r = 0.06 m = 6 cm
C.
r = 0.30 m = 30 cm
D.
r = 0.24 m = 24 cm
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ANSWER :
A. r = 0.12 m = 12 cm
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