Kinetic Interpretation of Temperature NEET Questions

Physics - Kinetic Theory of Gases

Kinetic Interpretation of Temperature MCQ Questions


1.
According to the kinetic interpretation of temperature, the absolute temperature of an ideal gas is directly proportional to:
A.
Total number of molecules in the gas
B.
Average rotational kinetic energy per molecule
C.
Average translational kinetic energy per molecule
D.
Total potential energy of all molecules
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ANSWER :
C. Average translational kinetic energy per molecule
2.
The kinetic theory gives the relation between average kinetic energy per molecule and absolute temperature T as:
A.
½ m v̄² = (1/2) kB T
B.
½ m v̄² = kB T
C.
½ m v̄² = 3 kB T
D.
½ m v̄² = (3/2) kB T
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ANSWER :
D. ½ m v̄² = (3/2) kB T
3.
The Boltzmann constant kB connects which two domains in kinetic interpretation of temperature?
A.
Gravitational domain and electromagnetic domain
B.
Macroscopic thermodynamic domain and microscopic molecular domain
C.
Quantum domain and classical domain
D.
Chemical domain and nuclear domain
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ANSWER :
B. Macroscopic thermodynamic domain and microscopic molecular domain
4.
From kinetic theory, PV = (2/3)E. Combined with the ideal gas equation PV = NkBT, the internal energy E of an ideal gas is:
A.
E = NkB T
B.
E = (1/2) NkB T
C.
E = (3/2) NkB T
D.
E = 3NkB T
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ANSWER :
C. E = (3/2) NkB T
5.
The kinetic interpretation of temperature implies that at absolute zero (T = 0 K), the average kinetic energy of gas molecules is:
A.
Maximum
B.
Equal to (3/2)R
C.
Zero
D.
Equal to kB
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ANSWER :
C. Zero
6.
The root mean square (rms) speed of gas molecules is given by kinetic theory as:
A.
vrms = √(3kBT / m)
B.
vrms = √(3kBT × m)
C.
vrms = √(kBT / m)
D.
vrms = √(2kBT / m)
😑 View Answer Rough Work Error
ANSWER :
A. vrms = √(3kBT / m)