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RMS Speed of Gas Molecules NEET Questions
NEET SYLLABUS
Physics - Kinetic Theory of Gases
Equation of State of a Perfect Gas
Work Done on Compressing a Gas
Kinetic Theory of Gases Assumptions
The Concept of Pressure
Kinetic Interpretation of Temperature
RMS Speed of Gas Molecules
Avogadro's Number
Degrees of Freedom, Law of Equipartition of Energy and Applications to Specific Heat Capacities of Gases
RMS Speed of Gas Molecules MCQ Questions
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1.
The RMS speed (vįµ£āā) of gas molecules is defined as:
A.
The square root of the mean (average) of the squares of the speeds of all the molecules in a gas
B.
The geometric mean of the speeds of all molecules
C.
The speed possessed by the maximum number of molecules
D.
The arithmetic mean of the speeds of all molecules
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ANSWER
:
A. The square root of the mean (average) of the squares of the speeds of all the molecules in a gas
2.
The formula for RMS speed of gas molecules in terms of temperature and molar mass is:
A.
vįµ£āā = ā(3RT/M), where R = universal gas constant, T = absolute temperature in Kelvin, M = molar mass in kg/mol
B.
vįµ£āā = ā(8RT/ĻM)
C.
vįµ£āā = ā(2RT/M)
D.
vįµ£āā = ā(RT/M)
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ANSWER
:
A. vįµ£āā = ā(3RT/M), where R = universal gas constant, T = absolute temperature in Kelvin, M = molar mass in kg/mol
3.
The formula for RMS speed in terms of Boltzmann constant kB and mass per molecule m is:
A.
vįµ£āā = ā(2kBT/m)
B.
vįµ£āā = ā(3kBT/m), where kB = Boltzmann constant = 1.38 Ć 10ā»Ā²Ā³ J/K and m = mass of one molecule
C.
vįµ£āā = ā(8kBT/Ļm)
D.
vįµ£āā = ā(kBT/m)
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ANSWER
:
B. vįµ£āā = ā(3kBT/m), where kB = Boltzmann constant = 1.38 Ć 10ā»Ā²Ā³ J/K and m = mass of one molecule
4.
The RMS speed formula can also be written in terms of pressure (P) and density (Ļ) of the gas as:
A.
vįµ£āā = ā(3PĻ)
B.
vįµ£āā = ā(2P/Ļ)
C.
vįµ£āā = ā(P/Ļ)
D.
vįµ£āā = ā(3P/Ļ), where P is the pressure of the gas and Ļ is its density
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ANSWER
:
D. vįµ£āā = ā(3P/Ļ), where P is the pressure of the gas and Ļ is its density
5.
The RMS speed is related to the average kinetic energy (KE) of gas molecules by:
A.
KE = (1/2)mvįµ£āā² = (3/2)kBT per molecule (or (3/2)RT per mole)
B.
KE = mvįµ£āā² = 3kBT per molecule
C.
KE = (1/3)mvįµ£āā² = (1/2)kBT per molecule
D.
KE = (1/2)mvįµ£āā = (3/2)kBT
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ANSWER
:
A. KE = (1/2)mvįµ£āā² = (3/2)kBT per molecule (or (3/2)RT per mole)
6.
The correct order of the three molecular speeds from highest to lowest is:
A.
vāā > vįµ£āā > vĢāᵄā
B.
vĢāᵄā > vįµ£āā > vāā
C.
vįµ£āā > vāā > vĢāᵄā
D.
vįµ£āā > vĢāᵄā > vāā (RMS speed > Average speed > Most Probable speed)
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ANSWER
:
D. vįµ£āā > vĢāᵄā > vāā (RMS speed > Average speed > Most Probable speed)
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