Principle of Superposition of Waves and Reflection of Waves NEET Online Quiz Question and Objective Questions Answers

Physics - Oscillations and Waves

Principle of Superposition of Waves and Reflection of Waves

Principle of Superposition of Waves and Reflection of Waves MCQ Questions

For two waves with equal amplitude a and phase difference φ, complete destructive interference (zero resultant amplitude) occurs when:

φ = 2π giving A = 0

φ = π (or 3π, 5π, …) giving A = 2a cos(π/2) = 0

φ = π/2 giving A = 0

φ = 0 giving A = 0

😑 View Answer Error

Two waves y₁ = a sin(kx−ωt) and y₂ = a sin(kx−ωt+π) are superposed. The resultant y = y₁ + y₂ equals:

y = 0 everywhere at all times (complete destructive interference)

y = 2a sin(kx−ωt+π/2)

y = a sin(2kx−2ωt)

y = 2a sin(kx−ωt)

😑 View Answer Error

Two waves with equal amplitude a are in phase (φ = 0). The resultant displacement and intensity compared to a single wave are:

Displacement amplitude = a; Intensity = same as single wave

Displacement amplitude = 2a; Intensity = 2 × single wave intensity

Displacement amplitude = a√2; Intensity = 2 × single wave intensity

Displacement amplitude = 2a (doubled); Intensity = 4 × single wave intensity

😑 View Answer Error

10.

The resultant of two waves y₁ = a sin(kx−ωt) and y₂ = a cos(kx−ωt) is:

y = 2a sin(kx−ωt) with amplitude 2a

y = a√2 sin(kx−ωt+π/4) with amplitude a√2 and phase shift π/4

y = a sin(kx−ωt+π/2) with amplitude a

y = 0 since sine and cosine cancel

😑 View Answer Error

11.

For two superposing waves A sin(kx−ωt) and B cos(kx−ωt), the resultant amplitude is:

√(A² − B²)

A − B

√(A² + B²)

A + B

😑 View Answer Error

12.

Two sinusoidal waves of unequal amplitudes a₁ and a₂ and phase difference φ are superposed. The resultant amplitude is:

√(a₁² + a₂² + 2a₁a₂ cosφ)

a₁ + a₂

a₁ − a₂

√(a₁² − a₂² + 2a₁a₂ sinφ)

😑 View Answer Error

Prev Next page