Chemical Principles Involved in the Qualitative Salt Analysis - Cations and Anions NEET Questions

Organic Chemistry - Principles of Practical Chemistry

Chemical Principles Involved in the Qualitative Salt Analysis - Cations and Anions MCQ Questions


1.
Precipitation in qualitative salt analysis occurs only when the:
A.
Ionic product (IP) = Solubility product (Ksp)
B.
Ionic product is equal to Kw (ionic product of water)
C.
Ionic product (IP) > Solubility product (Ksp)
D.
Ionic product (IP) < Solubility product (Ksp)
😑 View Answer Rough Work Error
ANSWER :
C. Ionic product (IP) > Solubility product (Ksp)
2.
If the ionic product of a sparingly soluble salt is less than its solubility product, then:
A.
The solution is saturated and equilibrium is established
B.
The salt decomposes
C.
Precipitate forms immediately
D.
The solution is unsaturated and no precipitate forms
😑 View Answer Rough Work Error
ANSWER :
D. The solution is unsaturated and no precipitate forms
3.
The principle on which the separation of cations into groups is based is:
A.
Difference in oxidation states only
B.
Difference in solubility products of their precipitates with the group reagent
C.
Difference in atomic masses of the cations
D.
Difference in colours of the cations
😑 View Answer Rough Work Error
ANSWER :
B. Difference in solubility products of their precipitates with the group reagent
4.
Common ion effect can be defined as:
A.
Increase in ionisation of a weak electrolyte by adding water
B.
Suppression of ionisation of a weak electrolyte by adding a strong electrolyte that supplies a common ion
C.
Equal solubility of two different salts in water
D.
Reaction between two ions to form a complex
😑 View Answer Rough Work Error
ANSWER :
B. Suppression of ionisation of a weak electrolyte by adding a strong electrolyte that supplies a common ion
5.
In group II analysis, dilute HCl is added before passing H2S in order to:
A.
Provide a chloride ion for the precipitation
B.
Convert all cations into chlorides
C.
Suppress the ionisation of H2S by common-ion effect, keeping [S2-] low so that only group II sulphides (low Ksp) precipitate
D.
Increase the [S2-] in solution
😑 View Answer Rough Work Error
ANSWER :
C. Suppress the ionisation of H2S by common-ion effect, keeping [S2-] low so that only group II sulphides (low Ksp) precipitate
6.
In group III analysis, NH4Cl is added before NH4OH because:
A.
It suppresses ionisation of NH4OH (common-ion effect) keeping [OH-] low so only group III hydroxides (low Ksp) precipitate
B.
It oxidises the cations to higher states
C.
It supplies extra Cl- which precipitates Ag+ and Pb2+
D.
It dissolves the hydroxides of group III
😑 View Answer Rough Work Error
ANSWER :
A. It suppresses ionisation of NH4OH (common-ion effect) keeping [OH-] low so only group III hydroxides (low Ksp) precipitate