SSC CGL 2023-17.07.2023-3 SSC Question Paper

SSC CGL 2023 Question Papers

SSC CGL 2023-17.07.2023-3 SSC Questions

61.
In a constituency, 90% of the total number of people on the electoral roll cast their vote during an election. 10% of the votes cast were declared invalid. Jeeta secured 60% of the valid votes. If Jeeta secured 91,800 valid votes, what was the total number of people on the electoral roll?
A.
216000
B.
225000
C.
180000
D.
200000
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ANSWER :
D. 200000
62.
12 men and 16 boys can do a piece of work in 5 days, while 13 men and 24 boys can do it in 4 days. In how many days can 29 men and 22 boys complete the work?
A.
2.5
B.
2.45
C.
2.6
D.
2.4
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ANSWER :
A. 2.5
63.
A bag contains ,550 in the form of 50 p, 25 p and 20 p coins in the ratio 2: 3: 5. The difference between the amounts that are contributed by the 50 p and the 20 p coins is:
A.
30
B.
20
C.
10
D.
0
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ANSWER :
D. 0
64.
The distance between the centres of two circles having radii 16 cm and 8 cm, is 26 cm. The length (in cm) of the direct common tangent of the two circles is:
A.
2√132
B.
√153
C.
2√153
D.
√132
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ANSWER :
C. 2√153
65.
Find the area of the sector of a circle with radius 5 cm and angle 60° (rounded off to one decimal).
A.
12.8 cm²
B.
14.1 cm²
C.
13.1 cm²
D.
15.1 cm²
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ANSWER :
C. 13.1 cm²
66.
Solve the following expression.
(-25) × 8 + (-25) × 2
A.
-210
B.
250
C.
-250
D.
210
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ANSWER :
C. -250
67.
The product of 277 and 323 is:
A.
89471
B.
88471
C.
91371
D.
89391
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ANSWER :
A. 89471
68.

If \(
\cos x = -\frac{1}{2},
\) x lies in third quadrant, then tanx = ?

A.

√3

B.

√3/2

C.

2/√3

D.

1/√3

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ANSWER :

A. √3

69.
A person took a loan at 5% per annum simple interest during the first year and with an increase of 0.5% simple interest every year from the second year onwards. After 4 years, he paid ₹74,600 as a total interest to settle the loan completely. How much was the loan?
A.
20000
B.
19000
C.
18000
D.
21000
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ANSWER :
A. 20000
70.

Using cos(A + B) = cosA cosB - sinA sinB, find the value of cos75°.

A.

\(
\frac{\sqrt{5} - 1}{4}
\)

B.

\(
\frac{\sqrt{5} + 1}{4}
\)

C.

\(
\frac{\sqrt{6} - \sqrt{2}}{4}
\)

D.

\(
\frac{\sqrt{6} + \sqrt{2}}{4}
\)

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ANSWER :

C. \(
\frac{\sqrt{6} - \sqrt{2}}{4}
\)