NDA & NA Exam (II)- 2024 - Mathematics Defence Question Paper

NDA Previous Year Question Papers Question Papers
NDA & NA Exam (II)- 2024 - Mathematics

NDA & NA Exam (II)- 2024 - Mathematics Defence Questions

41.
Consider the following for the next two (02) items that follow:
Let \( Z_{1} \) and \( Z_{2} \) be any two complex numbers such that \( Z_{1}^{2} + Z_{2}^{2} + Z_{1}Z_{2} = 0 \).

What is the value of \( \left|\frac{Z_{1}}{Z_{2}}\right| \)?
A.
1
B.
2
C.
3
D.
4
ANSWER :
A. 1
42.
What is the value of \( \frac{1}{2} + Re\left(\frac{Z_{1}}{Z_{2}}\right) \)?
A.
−1
B.
0
C.
1
D.
2
ANSWER :
B. 0
43.
Consider the following for the next two (02) items that follow:
The product of five consecutive terms of an AP is 229635. The first, second and fifth terms are in GP.

What is the common difference?
A.
3
B.
4
C.
5
D.
6
ANSWER :
D. 6
44.
What is the sum of all five terms?
A.
60
B.
65
C.
75
D.
80
ANSWER :
C. 75
45.
Consider the following for the next two (02) items that follow:
Let \( (8 + 3\sqrt{7})^{20} = U + V \) and \( (8 - 3\sqrt{7})^{20} = W \), where U is an integer and 0 < V < 1.

What is V + W equal to?
A.
8
B.
4
C.
2
D.
1
ANSWER :
D. 1
46.
What is the value of (U + V)W?
A.
\( \frac{1}{2} \)
B.
1
C.
\( \frac{3}{2} \)
D.
2
ANSWER :
B. 1
47.
Consider the following for the next two (02) items that follow:
The roots of the quadratic equation \( a^{2}(b^{2} - c^{2})x^{2} + b^{2}(c^{2} - a^{2})x + c^{2}(a^{2} - b^{2}) = 0 \) are equal \( (a^{2} \neq b^{2} \neq c^{2}) \).

Which one of the following statements is correct?
A.
\( a^{2}, b^{2}, c^{2} \) are in AP.
B.
\( a^{2}, b^{2}, c^{2} \) are in GP.
C.
\( a^{2}, b^{2}, c^{2} \) are in HP.
D.
\( a^{2}, b^{2}, c^{2} \) are neither in AP nor in GP nor in HP.
ANSWER :
C. \( a^{2}, b^{2}, c^{2} \) are in HP.
48.
Which one of the following is a root of the equation?
A.
\( \frac{b^{2}(c^{2} - a^{2})}{a^{2}(c^{2} - b^{2})} \)
B.
\( \frac{b^{2}(c^{2} - a^{2})}{a^{2}(b^{2} - c^{2})} \)
C.
\( \frac{b^{2}(c^{2} - a^{2})}{2a^{2}(c^{2} - b^{2})} \)
D.
\( \frac{b^{2}(c^{2} - a^{2})}{2a^{2}(b^{2} - c^{2})} \)
ANSWER :
C. \( \frac{b^{2}(c^{2} - a^{2})}{2a^{2}(c^{2} - b^{2})} \)
49.
Consider the following for the next two (02) items that follow:
Let \( A = \begin{bmatrix} 3 & -3 & 4 \\ 2 & -3 & 4 \\ 0 & -1 & 1 \end{bmatrix} \).

What is A(adj A) equal to?
A.
\( \begin{bmatrix} 5 & 0 & 0 \\ 0 & 5 & 0 \\ 0 & 0 & 5 \end{bmatrix} \)
B.
\( \begin{bmatrix} 2 & 0 & 0 \\ 0 & 2 & 0 \\ 0 & 0 & 2 \end{bmatrix} \)
C.
\( \begin{bmatrix} \frac{1}{2} & 0 & 0 \\ 0 & \frac{1}{2} & 0 \\ 0 & 0 & \frac{1}{2} \end{bmatrix} \)
D.
\( \begin{bmatrix} 1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1 \end{bmatrix} \)
ANSWER :
D. \( \begin{bmatrix} 1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1 \end{bmatrix} \)
50.
What is \( A^{-1} \) equal to?
A.
\( \begin{bmatrix} 1 & -1 & 0 \\ -2 & 3 & -4 \\ -2 & 3 & -3 \end{bmatrix} \)
B.
\( \begin{bmatrix} \frac{1}{2} & -\frac{1}{2} & 0 \\ -1 & \frac{3}{2} & -2 \\ -1 & \frac{3}{2} & -\frac{3}{2} \end{bmatrix} \)
C.
\( \begin{bmatrix} 2 & -2 & 0 \\ -4 & 6 & -8 \\ -4 & 6 & -6 \end{bmatrix} \)
D.
\( \begin{bmatrix} \frac{1}{5} & -\frac{1}{5} & 0 \\ -\frac{2}{5} & \frac{3}{5} & -\frac{4}{5} \\ -\frac{2}{5} & \frac{3}{5} & -\frac{3}{5} \end{bmatrix} \)
ANSWER :
A. \( \begin{bmatrix} 1 & -1 & 0 \\ -2 & 3 & -4 \\ -2 & 3 & -3 \end{bmatrix} \)