Motion of a Satellite ( Orbital Velocity, Time Period and Energy of Satellite ) NEET Questions

Physics - Gravitation

Motion of a Satellite ( Orbital Velocity, Time Period and Energy of Satellite ) MCQ Questions


1.
The orbital velocity of a satellite revolving in a circular orbit of radius (R_E + h) around the Earth (mass M_E) is derived by equating centripetal force to gravitational force. The correct expression is:
A.
V = √(GM_E·(R_E+h))
B.
V = √(GM_E/(R_E+h))
C.
V = GM_E/(R_E+h)
D.
V = √(2GM_E/(R_E+h))
😑 View Answer Rough Work Error
ANSWER :
B. V = √(GM_E/(R_E+h))
2.
The orbital speed of a satellite at height h above Earth's surface can also be written in terms of surface gravity g and Earth's radius R_E as:
A.
V = g·R_E/(R_E+h)
B.
V = √(g·R_E²/(R_E+h))
C.
V = g·R_E²/(R_E+h)²
D.
V = √(g/(R_E+h))
😑 View Answer Rough Work Error
ANSWER :
B. V = √(g·R_E²/(R_E+h))
3.
If the height of a satellite's orbit increases, its orbital speed:

NEET - 2019

A.
Increases
B.
Decreases
C.
Remains the same
D.
Becomes zero
😑 View Answer Rough Work Error
ANSWER :
B. Decreases
4.
The orbital speed of a satellite just above the Earth's surface (h ≈ 0) is approximately:
A.
11.2 km/s
B.
7.9 km/s
C.
3.0 km/s
D.
5.6 km/s
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ANSWER :
B. 7.9 km/s
5.
As the orbital height h of a satellite increases, its orbital speed V:
A.
Increases proportional to h
B.
Remains constant
C.
Decreases (V ∝ 1/√(R_E+h))
D.
First increases then decreases
😑 View Answer Rough Work Error
ANSWER :
C. Decreases (V ∝ 1/√(R_E+h))
6.
A satellite orbits at height h = R_E (where R_E = Earth's radius). Its orbital speed compared to the surface orbital speed V₀ = √(gR_E) is:
A.
V₀/√2
B.
V₀/2
C.
V₀/√2 (since (R_E+h) = 2R_E, V = √(gR_E²/2R_E) = √(gR_E/2) = V₀/√2)
D.
V₀/4
😑 View Answer Rough Work Error
ANSWER :
C. V₀/√2 (since (R_E+h) = 2R_E, V = √(gR_E²/2R_E) = √(gR_E/2) = V₀/√2)