Motion of a Satellite ( Orbital Velocity, Time Period and Energy of Satellite ) NEET Questions

Physics - Gravitation

Motion of a Satellite ( Orbital Velocity, Time Period and Energy of Satellite ) MCQ Questions


13.
The near-surface orbital period T₀ = 2π√(R_E/g) ≈ 85 minutes. This value can also be expressed as T₀ = 2π√(R_E³/GM_E). What is the physical significance of this minimum period?
A.
Satellites must orbit for at least 85 minutes to stay in orbit
B.
No artificial satellite can have a time period less than about 85 minutes while orbiting Earth
C.
The geostationary satellite has a period of 85 minutes
D.
The Earth completes one rotation in 85 minutes
😑 View Answer Rough Work Error
ANSWER :
B. No artificial satellite can have a time period less than about 85 minutes while orbiting Earth
14.
A satellite orbits at radius r from Earth's centre. If the orbital radius is increased to 4r, the new time period is (original period = T):
A.
4T
B.
2T
C.
8T
D.
16T
😑 View Answer Rough Work Error
ANSWER :
C. 8T
15.
The time period of a satellite orbiting Earth in a circular orbit is independent of:

NEET - 2016

A.
Mass of Earth
B.
Mass of the satellite
C.
Radius of the orbit
D.
Gravitational constant
😑 View Answer Rough Work Error
ANSWER :
B. Mass of the satellite
16.
The geostationary satellite has a time period of 24 hours and orbits at radius R_G from Earth's centre. A near-surface satellite has period T₀ ≈ 1.4 hours. The ratio R_G/R_E is approximately:
A.
(24/1.4)^(2/3) ≈ 6.6
B.
24/1.4 ≈ 17.1
C.
(24/1.4)^(1/2) ≈ 4.1
D.
(24/1.4)^2 ≈ 294
😑 View Answer Rough Work Error
ANSWER :
A. (24/1.4)^(2/3) ≈ 6.6
17.
The time period T and orbital radius r of a satellite satisfy T² = k·r³. The proportionality constant k for Earth satellites equals:
A.
4π²/GM_E
B.
GM_E/(4π²)
C.
4π²·GM_E
D.
GM_E·R_E²/4π²
😑 View Answer Rough Work Error
ANSWER :
A. 4π²/GM_E
18.
At what height above Earth's surface would a satellite's period be 2T₀ (twice the near-surface period)? (R_E = Earth's radius)
A.
h = R_E(2^(2/3) - 1) ≈ 0.587 R_E
B.
h = R_E
C.
h = 2R_E
D.
h = 3R_E
😑 View Answer Rough Work Error
ANSWER :
A. h = R_E(2^(2/3) - 1) ≈ 0.587 R_E