Motion of a Satellite ( Orbital Velocity, Time Period and Energy of Satellite ) NEET Questions

Physics - Gravitation
Motion of a Satellite ( Orbital Velocity, Time Period and Energy of Satellite )

Motion of a Satellite ( Orbital Velocity, Time Period and Energy of Satellite ) MCQ Questions


13.
The time period T and orbital radius r of a satellite satisfy T² = k·r³. The proportionality constant k for Earth satellites equals:
A.
4π²/GM_E
B.
GM_E/(4π²)
C.
4π²·GM_E
D.
GM_E·R_E²/4π²
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ANSWER :
A. 4π²/GM_E
14.
At what height above Earth's surface would a satellite's period be 2T₀ (twice the near-surface period)? (R_E = Earth's radius)
A.
h = R_E(2^(2/3) - 1) ≈ 0.587 R_E
B.
h = R_E
C.
h = 2R_E
D.
h = 3R_E
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ANSWER :
A. h = R_E(2^(2/3) - 1) ≈ 0.587 R_E
15.
The kinetic energy (KE) of a satellite of mass m in circular orbit of radius r = (R_E + h) around Earth is:
A.
KE = GM_Em/r
B.
KE = 2GM_Em/r
C.
KE = GM_Em/(2r)
D.
KE = GM_Em/r²
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ANSWER :
C. KE = GM_Em/(2r)
16.
The potential energy (PE) of a satellite of mass m at distance r from Earth's centre (with PE = 0 at infinity) is:
A.
PE = +GM_Em/r
B.
PE = -2GM_Em/r
C.
PE = -GM_Em/r
D.
PE = -GM_Em/(2r)
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ANSWER :
C. PE = -GM_Em/r
17.
The total mechanical energy of a satellite of mass m in circular orbit of radius r is:
A.
E = +GM_Em/(2r)
B.
E = -GM_Em/(2r)
C.
E = -GM_Em/r
D.
E = 0
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ANSWER :
B. E = -GM_Em/(2r)
18.
For a satellite in circular orbit, which of the following relations correctly describes the energies?
A.
KE = PE (both positive)
B.
KE = -PE/2, PE = 2E (negative), total E negative
C.
KE = PE = E = 0
D.
PE = -KE (both equal in magnitude, opposite sign), Total E = 0
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ANSWER :
B. KE = -PE/2, PE = 2E (negative), total E negative
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