Position-Time Graph NEET Questions

Position-Time Graph MCQ Questions

13.
A v-t graph shows two straight lines: one with steep positive slope and one with gentle positive slope. The steeper line represents:
A.
Greater speed
B.
Greater acceleration
C.
Greater displacement
D.
Greater time
ANSWER :
B. Greater acceleration
14.
On a v-t graph, an object has v = v₀ at t = 0 and v = 0 at t = t₁, with constant deceleration. The distance covered before stopping is represented by:
A.
Height of the triangle (v₀)
B.
Base of the triangle (t₁)
C.
Area of the triangle = ½v₀t₁
D.
Slope of the line = v₀/t₁
ANSWER :
C. Area of the triangle = ½v₀t₁
15.
The v-t graph of a particle is a horizontal line at v = 0 throughout. This means:
A.
Uniform acceleration
B.
The particle is permanently at rest
C.
Uniform deceleration
D.
Non-uniform motion
ANSWER :
B. The particle is permanently at rest
16.
For v-t graph of NCERT Fig 2.3(d), between 0 and t₁ the object moves in positive direction and between t₁ and t₂ in negative direction. The total distance covered (not displacement) from 0 to t₂ is:
A.
Zero
B.
Area of triangle from 0 to t₂ only
C.
Area below time axis only
D.
Sum of area above + area below time axis
ANSWER :
D. Sum of area above + area below time axis
17.
A v-t graph is a straight line with equation v = v₀ + at. The area under this line from 0 to t equals:
A.
v₀t
B.
½at²
C.
½(v − v₀)t
D.
v₀t + ½at²
ANSWER :
D. v₀t + ½at²
18.
A v-t graph has a kink (sharp corner) at some point. NCERT states this is physically unrealistic because:
A.
Acceleration would change abruptly (not continuously)
B.
Velocity cannot be measured there
C.
Area cannot be calculated
D.
The slope becomes infinite
ANSWER :
A. Acceleration would change abruptly (not continuously)