Position-Time Graph NEET Questions

Physics - Kinematics

Position-Time Graph MCQ Questions


7.
A v-t graph for uniform velocity u from t=0 to t=T is a horizontal line. The area under this curve equals:
A.
u/T
B.
u + T
C.
uT
D.
u²T
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ANSWER :
C. uT
8.
For uniformly accelerated motion, the v-t graph is a straight inclined line. The displacement in time t equals the area under this line, which is:
A.
½vt
B.
v₀t + ½at²
C.
vt
D.
½(v₀ + v)t
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ANSWER :
D. ½(v₀ + v)t
9.
On a v-t graph, a straight line with negative slope (starting from positive v) represents:
A.
Object moving backward
B.
Object decelerating (retarding) in positive direction
C.
Object at rest
D.
Uniform velocity
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ANSWER :
B. Object decelerating (retarding) in positive direction
10.
On a v-t graph, the line starts below the time axis with a negative slope (velocity more negative). This represents:
A.
Object decelerating
B.
Object moving in negative direction with increasing speed
C.
Object at rest
D.
Uniform positive velocity
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ANSWER :
B. Object moving in negative direction with increasing speed
11.
A v-t graph shows a straight line starting from positive v₀, crossing the time axis at t₁, then continuing with the same slope. The motion between 0 and t₁ is:
A.
Acceleration
B.
Uniform velocity
C.
Deceleration in positive direction
D.
Acceleration in negative direction
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ANSWER :
C. Deceleration in positive direction
12.
From the v-t graph, the average acceleration between t₁ and t₂ is given by:
A.
Slope of tangent at midpoint
B.
Slope of chord joining (t₁,v₁) and (t₂,v₂)
C.
Area under v-t curve
D.
Slope of tangent at t₁
😑 View Answer Rough Work Error
ANSWER :
B. Slope of chord joining (t₁,v₁) and (t₂,v₂)