Home
MCQ
TNPSC
TNPSC Group 1
TNPSC Group 2 2A
TNPSC Group 4 VAO
UPSC
TNTET
TNTET Paper 1
TNTET Paper 2
TNUSRB
TNUSRB PC
TNUSRB SI
Defence (NDA,CDS,AFCAT)
NDA
CDS
AFCAT
NEET
SSC
SSC CGL
SSC CHSL
SSC MTS
SSC GD
RRB
RRB NTPC
RRB Group D
RRB ALP
RRB JE
Blog
Reach Us
Login
Uniformly Accelerated Motion and its Relations, Velocity-Time, Position-Time Graph NEET Questions
NEET SYLLABUS
Physics - Kinematics
The Frame of Reference
Motion in a Straight Line
Position-Time Graph
Uniform and Non-Uniform Motion
Average Speed and Instantaneous Velocity
Uniformly Accelerated Motion and its Relations, Velocity-Time, Position-Time Graph
Scalars & Vectors (Addition and Subtraction, Scalar and Vector Products, Unit Vector, Resolution of a Vector)
Motion in a Plane, Projectile Motion and Uniform Circular Motion
Relative Velocity
Uniformly Accelerated Motion and its Relations, Velocity-Time, Position-Time Graph MCQ Questions
Prev
1
2
3
4
5
Next
1-5
13.
A train decelerates from 72 km/h to rest in 200 m. What is the deceleration? (72 km/h = 20 m/s)
A.
1 m/s²
B.
2 m/s²
C.
0.5 m/s²
D.
4 m/s²
😑
View Answer
Rough Work
Error
ANSWER
:
A. 1 m/s²
14.
The slope of a position-time (x-t) graph gives:
A.
Acceleration
B.
Displacement
C.
Velocity
D.
Distance
😑
View Answer
Rough Work
Error
ANSWER
:
C. Velocity
15.
For uniform motion (zero acceleration), the velocity-time graph is:
A.
A straight line inclined to the time axis
B.
A parabola
C.
A straight line parallel to the time axis
D.
A curve
😑
View Answer
Rough Work
Error
ANSWER
:
C. A straight line parallel to the time axis
16.
A ruler drop experiment is used to measure reaction time. The ruler falls under free fall. If it falls 20 cm, reaction time (g = 10 m/s²) is approximately:
A.
0.4 s
B.
0.2 s
C.
0.1 s
D.
0.04 s
😑
View Answer
Rough Work
Error
ANSWER
:
B. 0.2 s
17.
A body moving with velocity 20 m/s is uniformly decelerated to rest in 10 s. The retardation is:
A.
2 m/s²
B.
10 m/s²
C.
20 m/s²
D.
0.5 m/s²
😑
View Answer
Rough Work
Error
ANSWER
:
A. 2 m/s²
18.
The displacement of a particle in the nth second of uniformly accelerated motion is given by: (u=initial vel., a=accln.)
A.
u + a(2n-1)/2
B.
u + a(n-1)
C.
u*n + ½a*n²
D.
u + an
😑
View Answer
Rough Work
Error
ANSWER
:
A. u + a(2n-1)/2
Prev
1
2
3
4
5
Next
1-5
Your Name
*
Your Email
*
Justify your answer :
*
Send Message