Kohlrausch’s Law and its Applications NEET Questions

Physical Chemistry - Redox Reactions and Electrochemistry

Kohlrausch’s Law and its Applications MCQ Questions


7.
For BaCl₂, the limiting molar conductivity is:
A.
Λm°(BaCl₂) = λ°(Ba²⁺) + 2λ°(Cl⁻)
B.
Λm°(BaCl₂) = 2λ°(Ba²⁺) + λ°(Cl⁻)
C.
Λm°(BaCl₂) = λ°(Ba²⁺) + λ°(Cl⁻)
D.
Λm°(BaCl₂) = ½λ°(Ba²⁺) + λ°(Cl⁻)
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ANSWER :
A. Λm°(BaCl₂) = λ°(Ba²⁺) + 2λ°(Cl⁻)
8.
For Al₂(SO₄)₃, the limiting molar conductivity is:
A.
Λm° = 2λ°(Al³⁺) + 3λ°(SO₄²⁻)
B.
Λm° = λ°(Al³⁺) + λ°(SO₄²⁻)
C.
Λm° = 3λ°(Al³⁺) + 2λ°(SO₄²⁻)
D.
Λm° = ½λ°(Al³⁺) + ⅓λ°(SO₄²⁻)
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ANSWER :
A. Λm° = 2λ°(Al³⁺) + 3λ°(SO₄²⁻)
9.
For K₄[Fe(CN)₆], the limiting molar conductivity is:
A.
Λm° = λ°(K⁺) + λ°[Fe(CN)₆]⁴⁻
B.
Λm° = 4λ°(K⁺) + 4λ°[Fe(CN)₆]⁴⁻
C.
Λm° = λ°(K⁺) + 4λ°[Fe(CN)₆]⁴⁻
D.
Λm° = 4λ°(K⁺) + λ°[Fe(CN)₆]⁴⁻
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ANSWER :
D. Λm° = 4λ°(K⁺) + λ°[Fe(CN)₆]⁴⁻
10.
For MgSO₄, the limiting molar conductivity equals:
A.
2λ°(Mg²⁺) + λ°(SO₄²⁻)
B.
½λ°(Mg²⁺) + ½λ°(SO₄²⁻)
C.
λ°(Mg²⁺) + 2λ°(SO₄²⁻)
D.
λ°(Mg²⁺) + λ°(SO₄²⁻)
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ANSWER :
D. λ°(Mg²⁺) + λ°(SO₄²⁻)
11.
For (NH₄)₂SO₄, the limiting molar conductivity is:
A.
½λ°(NH₄⁺) + λ°(SO₄²⁻)
B.
2λ°(NH₄⁺) + λ°(SO₄²⁻)
C.
λ°(NH₄⁺) + 2λ°(SO₄²⁻)
D.
λ°(NH₄⁺) + λ°(SO₄²⁻)
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ANSWER :
B. 2λ°(NH₄⁺) + λ°(SO₄²⁻)
12.
For Ca(NO₃)₂, Λm° equals:
A.
½λ°(Ca²⁺) + ½λ°(NO₃⁻)
B.
λ°(Ca²⁺) + λ°(NO₃⁻)
C.
λ°(Ca²⁺) + 2λ°(NO₃⁻)
D.
2λ°(Ca²⁺) + λ°(NO₃⁻)
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ANSWER :
C. λ°(Ca²⁺) + 2λ°(NO₃⁻)