Kohlrausch’s Law and its Applications NEET Questions

Physical Chemistry - Redox Reactions and Electrochemistry

Kohlrausch’s Law and its Applications MCQ Questions


13.
The most important application of Kohlrausch's law is the determination of:
A.
Conductivity of pure water
B.
Cell constant of conductivity cell
C.
Λm° of strong electrolytes
D.
Λm° of weak electrolytes
😑 View Answer Rough Work Error
ANSWER :
D. Λm° of weak electrolytes
14.
Λm° of acetic acid (CH₃COOH) can be calculated from Λm° of:
A.
CH₃COOH, NaCl and KCl
B.
CH₃COOK, KOH and KCl
C.
CH₃COONa, HCl and NaCl
D.
CH₃COONa, NaOH and HCl
😑 View Answer Rough Work Error
ANSWER :
C. CH₃COONa, HCl and NaCl
15.
Λm°(CH₃COOH) is given by which combination?
A.
Λm°(CH₃COONa) − Λm°(HCl) − Λm°(NaCl)
B.
Λm°(CH₃COONa) + Λm°(HCl) − Λm°(NaCl)
C.
Λm°(CH₃COONa) − Λm°(HCl) + Λm°(NaCl)
D.
Λm°(CH₃COONa) + Λm°(HCl) + Λm°(NaCl)
😑 View Answer Rough Work Error
ANSWER :
B. Λm°(CH₃COONa) + Λm°(HCl) − Λm°(NaCl)
16.
To calculate Λm°(NH₄OH) using Kohlrausch's law, the appropriate combination of strong electrolytes is:
A.
Λm°(NH₄Cl) + Λm°(NaOH) + Λm°(NaCl)
B.
Λm°(NH₄Cl) − Λm°(NaOH) + Λm°(NaCl)
C.
Λm°(NH₄OH) = Λm°(NH₄Cl) only
D.
Λm°(NH₄Cl) + Λm°(NaOH) − Λm°(NaCl)
😑 View Answer Rough Work Error
ANSWER :
D. Λm°(NH₄Cl) + Λm°(NaOH) − Λm°(NaCl)
17.
Why can't Λm° of a weak electrolyte be obtained directly by extrapolating Λm vs √c plot?
A.
The plot has zero slope at c = 0
B.
The plot is non-linear and rises steeply near c = 0
C.
Λm of weak electrolytes is independent of concentration
D.
Weak electrolytes do not conduct electricity
😑 View Answer Rough Work Error
ANSWER :
B. The plot is non-linear and rises steeply near c = 0
18.
Kohlrausch's law is used to calculate the degree of dissociation (α) of a weak electrolyte using:
A.
α = Λm° / Λmᶜ
B.
α = Λmᶜ / Λm°
C.
α = Λmᶜ + Λm°
D.
α = Λmᶜ × Λm°
😑 View Answer Rough Work Error
ANSWER :
B. α = Λmᶜ / Λm°