Isothermal & Adiabatic Processes NEET Questions

Physics - Thermodynamics

Isothermal & Adiabatic Processes MCQ Questions


7.
For an isothermal process of an ideal gas, since ΔU = 0, the First Law gives:
A.
ΔQ = 0
B.
ΔQ = −ΔW
C.
ΔW = 0
D.
ΔQ = ΔW — heat supplied equals work done by gas
😑 View Answer Rough Work Error
ANSWER :
D. ΔQ = ΔW — heat supplied equals work done by gas
8.
Work done by an ideal gas in isothermal expansion from volume V₁ to V₂ at temperature T is:
A.
W = nR(T₂ − T₁)/(γ − 1)
B.
W = nRT(V₂ − V₁)
C.
W = nRT ln(V₂/V₁)
D.
W = P₁(V₂ − V₁)
😑 View Answer Rough Work Error
ANSWER :
C. W = nRT ln(V₂/V₁)
9.
In an isothermal expansion, W > 0 and ΔU = 0. NCERT states: 'heat supplied to the gas equals the work done by the gas.' For isothermal compression (V₂ < V₁):
A.
ΔU > 0 for compression
B.
W < 0 (work done ON gas) and Q < 0 (heat released by gas to reservoir)
C.
Gas absorbs heat and does positive work
D.
W = 0 and Q = 0
😑 View Answer Rough Work Error
ANSWER :
B. W < 0 (work done ON gas) and Q < 0 (heat released by gas to reservoir)
10.
One mole of ideal gas undergoes isothermal expansion at 300 K, volume doubles (V₂ = 2V₁). Work done is: (R = 8.3 J/mol·K, ln 2 = 0.693)
A.
3452 J
B.
1245 J
C.
1726 J
D.
2490 J
😑 View Answer Rough Work Error
ANSWER :
C. 1726 J
11.
For isothermal expansion of ideal gas: if volume increases to 4 times its initial value (V₂ = 4V₁) at T = 300 K for 2 moles, work done is: (R = 8.3 J/mol·K)
A.
13808 J
B.
6904 J
C.
1726 J
D.
3452 J
😑 View Answer Rough Work Error
ANSWER :
B. 6904 J
12.
The work done in isothermal compression of 1 mole of ideal gas at 300 K from V₁ to V₁/2 is: (R = 8.3 J/mol·K, ln 2 = 0.693)
A.
+1726 J
B.
863 J
C.
−1726 J
D.
0 J
😑 View Answer Rough Work Error
ANSWER :
C. −1726 J