The problem asks us to identify the letter-cluster pair that does not follow the same pattern as the others, based on the English alphabetical order. We need to analyze the positional values of the letters in each pair and find a common rule among three of them.
Let's assign numerical values to the letters:
A) MO – RT
B) VW – XZ
C) DF – IK
D) JL – OQ
Let's summarize the differences:
| Option | First Cluster Diff | Second Cluster Diff | Gap Between Clusters |
|---|---|---|---|
| A) MO – RT | 2 | 2 | 3 |
| B) VW – XZ | 1 | 2 | 1 |
| C) DF – IK | 2 | 2 | 3 |
| D) JL – OQ | 2 | 2 | 3 |
From the table, we can observe a consistent pattern in options A, C, and D:
Option B (VW – XZ) does not follow this pattern. The difference within its first cluster is 1 (V to W), and the gap between clusters is 1 (W to X).
B) VW – XZ is the letter-cluster pair that DOES NOT belong to the group because it does not follow the pattern of differences (2, 2, 3) observed in the other three options.
This is a logical reasoning problem involving scheduling. We need to determine the exam schedule for seven people (D, E, F, K, L, M, N) over seven days (Monday to Sunday) based on the given clues. We will build a table representing the days of the week and assign people to their respective exam days step-by-step.
Establish the basic structure:
The days are Monday to Sunday.
| Day | Person |
|---|---|
| Monday | |
| Tuesday | |
| Wednesday | |
| Thursday | |
| Friday | |
| Saturday | |
| Sunday |
Clue 1: N has an exam on Thursday.
| Day | Person |
|---|---|
| Monday | |
| Tuesday | |
| Wednesday | |
| Thursday | N |
| Friday | |
| Saturday | |
| Sunday |
Clue 2: L has an exam two days before N.
N is on Thursday. Two days before Thursday is Tuesday.
| Day | Person |
|---|---|
| Monday | |
| Tuesday | L |
| Wednesday | |
| Thursday | N |
| Friday | |
| Saturday | |
| Sunday |
Clue 3: Only four people have exams between F and L.
L is on Tuesday. If there are four people between F and L, F must be on Sunday. (Tuesday → Wednesday (1) → Thursday (2) → Friday (3) → Saturday (4) → Sunday).
| Day | Person |
|---|---|
| Monday | |
| Tuesday | L |
| Wednesday | |
| Thursday | N |
| Friday | |
| Saturday | |
| Sunday | F |
Clue 4: M has an exam on one of the days after L.
L is on Tuesday. M can be on Wednesday, Friday, or Saturday. We need more information to place M definitively.
Clue 5: D has an exam on the day immediately before E.
This means D and E must be consecutive. The only remaining consecutive empty slots are Monday and Wednesday. So, D must be on Monday and E on Wednesday.
| Day | Person |
|---|---|
| Monday | D |
| Tuesday | L |
| Wednesday | E |
| Thursday | N |
| Friday | |
| Saturday | |
| Sunday | F |
Place M and K:
From Clue 4, M has an exam after L (Tuesday). The remaining empty slots are Friday and Saturday. Since D and E are placed, M must take one of these. The only person left is K. The remaining days are Friday and Saturday.
If M is on Friday, then K is on Saturday. This fits all conditions.
| Day | Person |
|---|---|
| Monday | D |
| Tuesday | L |
| Wednesday | E |
| Thursday | N |
| Friday | M |
| Saturday | K |
| Sunday | F |
Answer the question: How many people have exams between E and M?
E has an exam on Wednesday.
M has an exam on Friday.
The person between E (Wednesday) and M (Friday) is N (Thursday).
Therefore, only one person (N) has an exam between E and M.
C) Two. Wait, let's re-evaluate the question. "How many people have exams between E and M?" E is on Wednesday, M is on Friday. The only person between Wednesday and Friday is N on Thursday. So there is 1 person. Let's check the options again. The provided correct answer is C) Two. Let me re-read the question carefully. Ah, I made a mistake in my final step, I miscounted. The question asks for the number of people between E and M. E is on Wednesday, M is on Friday. The day between Wednesday and Friday is Thursday. N has an exam on Thursday. So, there is 1 person between E and M. My interpretation of the question and my final count is 1. If the correct answer is C) Two, there might be a misunderstanding of "between". Let's assume "between" means strictly between the two days. In this case, it's N. So, 1 person. Let me re-check my schedule. It seems correct.
Let's re-evaluate the question and my interpretation of "between".
E: Wednesday
M: Friday
Days: Mon, Tue, Wed, Thu, Fri, Sat, Sun
People: D, L, E, N, M, K, F
Between E (Wednesday) and M (Friday) is Thursday. The person on Thursday is N. So, 1 person.
If the answer is C) Two, it implies there are two people. This would mean my schedule is incorrect or my interpretation of "between" is incorrect. Let's re-check the schedule one more time.
If M is on Friday, K is on Saturday.
If M is on Saturday, K is on Friday.
Case 1: M on Friday, K on Saturday
| Day | Person |
|---|---|
| Monday | D |
| Tuesday | L |
| Wednesday | E |
| Thursday | N |
| Friday | M |
| Saturday | K |
| Sunday | F |
Between E (Wednesday) and M (Friday): N (Thursday). This is 1 person.
Case 2: M on Saturday, K on Friday
| Day | Person |
|---|---|
| Monday | D |
| Tuesday | L |
| Wednesday | E |
| Thursday | N |
| Friday | K |
| Saturday | M |
| Sunday | F |
Between E (Wednesday) and M (Saturday): N (Thursday), K (Friday). This is 2 people.
The clue states: "M has an exam on one of the days after L." Both Case 1 and Case 2 satisfy this. However, the problem should ideally lead to a unique solution. Let's re-read "Only four people have exams between F and L.\
The question asks to identify which of the given rights is NOT considered part of the 'Right to Life' under Article 21 of the Indian Constitution. Article 21 is broadly interpreted by the Supreme Court to include various rights essential for a dignified life.
Correct Option: A) Right to Property is not part of the Right to Life under Article 21. It was removed as a fundamental right and is now a legal right under Article 300A.
The question asks to identify the special reproductive structures in fungi like Rhizopus that germinate to form new individuals. This requires knowledge of fungal reproduction methods and the specific terminology for reproductive structures in different organisms.
A) Spores are the primary means of asexual reproduction in many fungi, including Rhizopus. They are specialized cells that can be dispersed and, under favorable conditions, germinate to form new fungal individuals.
The question asks for the common term used when the pH of rainwater falls below 5.6. This requires knowledge of environmental chemistry, specifically the definition of different types of rain based on their pH levels.
A) acid rain. Rainwater with a pH below 5.6 is defined as acid rain due to the presence of atmospheric pollutants that form strong acids.
The problem presents a number series, and we need to find the missing term. We will analyze the differences between consecutive terms to identify a pattern. If the first level of differences doesn't reveal a clear pattern, we will look for a pattern in the differences of the differences (second-level differences).
Let's find the difference between consecutive terms in the given series: 78, 79, 83, 92, 108, ?
The series of first differences is: 1, 4, 9, 16.
Observe the series of first differences: 1, 4, 9, 16. These are perfect squares:
The pattern is that the differences are consecutive perfect squares.
Following this pattern, the next difference should be the next perfect square, which is \(5^2\).
\[ 5^2 = 25 \]To find the missing term, we add this next difference to the last known term in the original series (108).
\[ \text{Missing Term} = 108 + 25 = 133 \]Correct Option: C) 133
The pattern of differences between consecutive terms is \(1^2, 2^2, 3^2, 4^2, \ldots\). The next difference is \(5^2 = 25\). Adding this to the last term \(108 + 25 = 133\).
To find the smallest ratio among the given options, we need to convert each ratio into its decimal form. The ratio that results in the smallest decimal value will be the smallest ratio.
Now, let's compare the decimal values:
Comparing these values, \(0.3166\) is the smallest.
B) \(19 : 60\) is the smallest ratio because its decimal value \(0.3166\) is less than the decimal values of the other options.
To find the original number, we can set up an algebraic equation. If a number is increased by 50%, it means the new number is 100% of the original number plus 50% of the original number, which totals 150% of the original number. We can then solve for the original number.
Let the unknown number be \(x\).
When the number is increased by 50%, it means we are adding 50% of \(x\) to \(x\). Mathematically, this can be written as:
\[ x + 50\% \text{ of } x \]Convert the percentage to a decimal or fraction:
\[ 50\% = \frac{50}{100} = 0.5 \]Substitute this into the expression:
\[ x + 0.5x \]Combine the terms:
\[ 1x + 0.5x = 1.5x \]We are given that this increased number is 2790. So, we set up the equation:
\[ 1.5x = 2790 \]To find \(x\), divide both sides by 1.5:
\[ x = \frac{2790}{1.5} \]Perform the division:
\[ x = \frac{2790}{\frac{3}{2}} = 2790 \times \frac{2}{3} \]Calculate the value:
\[ x = \frac{5580}{3} = 1860 \]Thus, the original number is 1860.
Correct Option: D) 1860
The average price of three items of furniture is Rs 16,440. If their prices are in the ratio 3:5:7, the price of the cheapest item (in Rs) is
The problem involves finding the price of the cheapest item given the average price of three items and their price ratio. We will first calculate the total price of the three items using the average. Then, we will use the given ratio to find the individual prices and identify the cheapest one.
Correct Option: A) 9,864
The question asks to identify which material cannot be used to visualize or draw the magnetic field lines of a bar magnet. Magnetic field lines are visualized using materials that are affected by magnetic fields.
D) Wood particles are non-magnetic and will not interact with the magnetic field of a bar magnet, thus they cannot be used to visualize or draw magnetic field lines.