SSC CHSL 2021-06.08.2021-3 SSC Question Paper

SSC CHSL 2021-06.08.2021-3 SSC Questions

61.

If 3cotA = 4tanA and A is an acute angle, then what will be the value of sec A?

A.

\(\frac{\sqrt{7}}{2}\)

B.

\(\frac{\sqrt{21}}{3}\)

C.

\(\frac{1}{\sqrt{3}}\)

D.

\(\frac{1}{2}\)

ANSWER :

A. \(\frac{\sqrt{7}}{2}\)

62.
The present population of a village (males and females) is 7640. If the number of males increases by 25% and the number of females increases by 15%, then the population will become 9214. The difference between the present population of males and females in the village is:
A.
820
B.
960
C.
940
D.
920
ANSWER :
D. 920
63.

What is the value of \(\frac{\cos^{2}20^{\circ} + \cos^{2}70^{\circ}}{\sin^{2}90^{\circ}} - \tan^{2}45^{\circ}\ ?\)

A.

0

B.

1

C.

-2

D.

-1

ANSWER :

A. 0

64.
Two positive numbers are in the ratio 8 : 13. If the sum of their squares is 2097, then the sum of the two numbers is:
A.
65
B.
63
C.
64
D.
60
ANSWER :
B. 63
65.
When a positive integer 'n' is divided by 12, the remainder is 5. What will be the remainder if 8n² + 7 is divided by 12?
A.
2
B.
5
C.
3
D.
4
ANSWER :
C. 3
66.

Simplify the following expression:
\(\frac{3\frac{2}{3}-5\frac{7}{9}\div\frac{1}{3}\times1\frac{2}{13}}{\frac{2}{3}\ \text{of}\ 1\frac{1}{3}\div\frac{1}{3}}\)

A.

\(-2\frac{77}{104}\)

B.

\(-29\frac{2}{5}\)

C.

\(-6\frac{1}{8}\)

D.

\(-14\frac{1}{4}\)

ANSWER :

C. \(-6\frac{1}{8}\)

67.

A customer availed a 10% discount on the purchase of a table and paid ₹4,950 for it. How much money would he have saved if he had bargained to get 12% discount?

A.

₹660

B.

₹99

C.

₹108.9

D.

₹110

ANSWER :

D. ₹110

68.

If \(x - \frac{1}{x} = 2\sqrt{2}\) , then what will be the value of \(x^{3} - \frac{1}{x^{3}}\ ?\)

A.

\(22\sqrt{2}\)

B.

\(12\sqrt{2}\)

C.

\(10\sqrt{2}\)

D.

\(20\sqrt{2}\)

ANSWER :

A. \(22\sqrt{2}\)

69.
Study the given pie chart and answer the question that follows.
Total number of students admitted in a college = 700.
Distribution of the percentage of students in various courses.
Percentage-wise distribution of the number of boys.
The difference between the number of boys and the number of girls admitted in B.Com. is:
A.
65
B.
70
C.
75
D.
60
ANSWER :
B. 70
70.

If x⁓ − 12x² + 1 = 0, then what will be the value of  \(x^{4} + \frac{1}{x^{4}}\ ?\)

A.

142

B.

146

C.

10

D.

144

ANSWER :

A. 142