If 0° < θ < 90°, then \(\dfrac{(1-\sin\theta)(\sec\theta + \tan\theta)\tan\theta}{(\tan\theta + \sec\theta + 1)(\cot\theta - \csc\theta + 1)} = ?\)
sin θ
\(\dfrac{\sin\theta}{2}\)
cos θ
\(\dfrac{\cos\theta}{2}\)
In a survey it was found that in a constituency, 55% of voters are male and the rest are female. 40% of the male voters are literate and \(33\dfrac{1}{3}\%\) of the female voters are illiterate. What percentage of the voters are literate?
The value of \(\dfrac{96 \div 16 \text{ of } 2 - 128 \times 2 \div 32 + 15 \text{ of } 4}{\dfrac{5}{6} \text{ of } \dfrac{2}{3}\left(1\dfrac{1}{3} - \dfrac{1}{4} - \dfrac{1}{6}\right)}\) is: