This question tests knowledge about the gravitational force and its variation between Earth and the Moon. The weight of an object is the force of gravity acting on it. This force depends on the mass of the object and the acceleration due to gravity of the celestial body it is on.
D) 1/6 th of the weight on Earth. As derived, the acceleration due to gravity on the Moon is approximately one-sixth of that on Earth, leading to an object's weight on the Moon being one-sixth of its weight on Earth.
The question asks to identify the specific name for the upward force exerted by a liquid on an immersed object. This is a fundamental concept in fluid mechanics, particularly related to buoyancy.
Correct Option: B) Buoyant force is the upward force exerted by a fluid that opposes the weight of an immersed object. This phenomenon is described by Archimedes' principle.
The question asks about the force responsible for leaves falling to the ground. This is a common phenomenon observed daily and is directly related to a fundamental force of nature that attracts objects towards the Earth.
Correct Option: A) Gravitational force is the attractive force exerted by the Earth on the leaf, pulling it downwards towards the ground. This is why all objects, including leaves, fall towards the Earth when released or detached.
The question asks about the specific force experienced by objects when they are immersed in a fluid. This phenomenon is a fundamental concept in fluid mechanics, particularly related to Archimedes' principle.
Correct Option: B) Force of buoyancy
The question asks about factors that do NOT influence the gravitational force between two bodies. We need to recall Newton's Law of Universal Gravitation and identify which of the given options is not a component of the formula.
Correct Option: D) The gravitational force is a fundamental interaction between masses and is not affected by the medium (e.g., air, water, vacuum) between the two bodies. The universal gravitational constant \(G\) is indeed universal.
To find the SI unit of the Gravitational Constant (\(G\)), we use Newton's Law of Universal Gravitation, which relates the gravitational force between two objects to their masses and the distance between them. By rearranging the formula, we can isolate \(G\) and then substitute the SI units of each variable to determine its unit.
The formula for the gravitational force (\(F\)) between two objects with masses \(m_1\) and \(m_2\), separated by a distance \(r\), is given by:
\[ F = G \frac{m_1 m_2}{r^2} \]To find the unit of \(G\), we need to isolate \(G\):
\[ G = \frac{F r^2}{m_1 m_2} \]Now, substitute these units into the rearranged formula for \(G\):
\[ \text{Unit of } G = \frac{(\text{N}) (\text{m})^2}{(\text{kg}) (\text{kg})} \]\[ \text{Unit of } G = \frac{\text{N m}^2}{\text{kg}^2} \]The unit can be written as:
\[ \text{Unit of } G = \text{N m}^2 \text{ kg}^{-2} \]A) Nm2 kg-2: This matches the derived SI unit for the Gravitational Constant.