If water vapour is assumed to be a perfect gas, molar enthalpy change for vaporisation of 1 mol of water at 1 bar and 100°C is 41kJ mol–1. Calculate the internal energy change, when 1 mol of water is vapourised at 1 bar pressure and 100°C.
393.66 L atm
37.904 kJ mol–1
q = – w = pex (10 – 2) = -8 litre-atm
∆H =UA– UB