The P-Block Elements NDA Questions

The P-Block Elements MCQ Questions

1.
The general valence shell electronic configuration of Group 15 elements is:
A.
ns²np³ — half-filled p-subshell giving extra stability
B.
ns²np⁵
C.
ns²np²
D.
ns²np⁴
ANSWER :
A. ns²np³ — half-filled p-subshell giving extra stability
2.
Why does nitrogen NOT form NX₅ (pentahalides) while phosphorus forms PCl₅?
A.
Nitrogen has a smaller atomic radius than phosphorus so it repels halogen atoms
B.
NX₅ compounds are thermodynamically unstable for all Group 15 elements
C.
Nitrogen lacks d-orbitals in its valence shell (n=2 has only s and p orbitals), so it cannot expand its octet beyond 4 bonds; phosphorus (n=3) has available 3d orbitals to accommodate 5 bonds
D.
Nitrogen is too electronegative to form bonds with halogens
ANSWER :
C. Nitrogen lacks d-orbitals in its valence shell (n=2 has only s and p orbitals), so it cannot expand its octet beyond 4 bonds; phosphorus (n=3) has available 3d orbitals to accommodate 5 bonds
3.
The INERT PAIR EFFECT in Group 15 elements explains why:
A.
Electronegativity increases from N to Bi
B.
The metallic character decreases down the group
C.
All Group 15 elements prefer -3 oxidation state exclusively
D.
The stability of +5 oxidation state decreases and +3 oxidation state increases down the group — the ns² electrons become increasingly reluctant to participate in bonding
ANSWER :
D. The stability of +5 oxidation state decreases and +3 oxidation state increases down the group — the ns² electrons become increasingly reluctant to participate in bonding
4.
The stability of +5 oxidation state in Group 15 decreases down the group. The ONLY well-characterised Bi(V) compound is:
A.
BiH₅
B.
BiF₅ (bismuth pentafluoride)
C.
Bi₂O₅
D.
BiCl₅
ANSWER :
B. BiF₅ (bismuth pentafluoride)
5.
DINITROGEN (N₂) is prepared in the laboratory by heating:
A.
Heating sodium nitrate (NaNO₃) strongly
B.
Electrolysis of water
C.
Ammonium dichromate: (NH₄)₂Cr₂O₇ → N₂ + Cr₂O₃ + 4H₂O, or by heating ammonium nitrite solution: NH₄Cl + NaNO₂ → N₂ + 2H₂O + NaCl
D.
Fractional distillation of liquid air (industrial method, not lab method)
ANSWER :
C. Ammonium dichromate: (NH₄)₂Cr₂O₇ → N₂ + Cr₂O₃ + 4H₂O, or by heating ammonium nitrite solution: NH₄Cl + NaNO₂ → N₂ + 2H₂O + NaCl
6.
AMMONIA (NH₃) is manufactured industrially by the HABER PROCESS. The reaction is:
A.
N₂ + H₂ → NH₂ with KOH catalyst
B.
N₂ + 3H₂ ⇌ 2NH₃ (conditions: 200 atm pressure, 700 K temperature, Fe catalyst with Mo as promoter)
C.
2N₂ + 3H₂ → 2N₂H₃ with Ni catalyst
D.
N₂ + 2H₂ → N₂H₄ at high temperature
ANSWER :
B. N₂ + 3H₂ ⇌ 2NH₃ (conditions: 200 atm pressure, 700 K temperature, Fe catalyst with Mo as promoter)