Enthalpy of Neutralization of Strong Acid and Strong Base NEET Questions

Enthalpy of Neutralization of Strong Acid and Strong Base MCQ Questions

13.
Which of the following statements is NOT correct?
A.
Enthalpy of neutralization is the heat change per gram equivalent
B.
It is approximately -57.1 kJ/mol for strong acid-strong base
C.
Enthalpy of neutralization of strong acid by strong base depends on the cation present
D.
It is always exothermic
ANSWER :
C. Enthalpy of neutralization of strong acid by strong base depends on the cation present
14.
If 50 mL of 0.5 M HCl is added to 50 mL of 0.5 M KOH at 25°C, find ΔT (assume ρ = 1 g/mL, s = 4.184 J/g·°C):
A.
3.41°C (Q = 0.025 × 57.1 = 1428 J; ΔT = 1428/(100 × 4.184))
B.
6.83°C
C.
1.71°C
D.
13.6°C
ANSWER :
A. 3.41°C (Q = 0.025 × 57.1 = 1428 J; ΔT = 1428/(100 × 4.184))
15.
If 0.1 M HCl (50 mL) is mixed with 0.1 M NaOH (50 mL) in calorimeter, ΔT observed = 0.68°C. Calculated ΔH(neutralization):
A.
-569 kJ/mol
B.
-56.9 kJ/mol
C.
-100 kJ/mol
D.
-5.69 kJ/mol
ANSWER :
B. -56.9 kJ/mol
16.
In the equation ΔH = -Q/n, n represents:
A.
Avogadro number
B.
Moles of acid
C.
Moles of any reagent
D.
Moles of water formed in the reaction
ANSWER :
D. Moles of water formed in the reaction
17.
Why should concentrated acid and base NOT be used for accurate enthalpy of neutralization?
A.
They are too expensive
B.
Temperature rise is too small
C.
Heat of dilution adds error; ions are not fully solvated
D.
Reaction is slow
ANSWER :
C. Heat of dilution adds error; ions are not fully solvated
18.
The pH of solution after complete neutralization of HCl by NaOH (1:1) is:
A.
7 (neutral)
B.
0
C.
Less than 7 (acidic)
D.
Greater than 7 (basic)
ANSWER :
A. 7 (neutral)