This is a syllogism problem. We will use Venn diagrams to represent the given statements and then evaluate the conclusions based on these diagrams. The key is to assume the statements are true, even if they contradict common knowledge.
Represent Statement 1: "All chairs are tables."
This means that the set of "Chairs" is entirely contained within the set of "Tables".
\[ \text{Chairs} \subseteq \text{Tables} \]
Visually, draw a small circle for Chairs inside a larger circle for Tables.
Represent Statement 2: "No table is a bed."
This means that the set of "Tables" and the set of "Beds" have no common elements. They are mutually exclusive.
\[ \text{Tables} \cap \text{Beds} = \emptyset \]
Visually, draw a circle for Beds completely separate from the circle for Tables.
Evaluate Conclusion (I): "Some beds are chairs."
From Statement 1, all chairs are inside tables. From Statement 2, tables and beds are completely separate. Therefore, chairs (which are inside tables) cannot have any overlap with beds. This conclusion is false.
Evaluate Conclusion (II): "No bed is a table."
This conclusion is a direct restatement of Statement 2. Since Statement 2 is given as true, this conclusion must also be true.
Correct Option: A) Only conclusion (II) follows.
The question asks to identify the tissue type primarily responsible for movement in the human body. We need to recall the primary functions of each of the four basic tissue types: nervous, muscular, epithelial, and connective tissue.
Correct Option: B) Muscular tissue is specialized for contraction, which allows for movement of the body, internal organs, and substances within the body.
The question asks to identify the sport associated with the Ranji Trophy. This is a general knowledge question related to Indian sports. Recalling major domestic sports tournaments in India will help in identifying the correct answer.
D) Cricket โ The Ranji Trophy is India's most prestigious domestic first-class cricket competition, named after the first Indian Test cricketer, Ranjitsinhji.
The problem presents a series of three-letter combinations. We need to identify the pattern in the English alphabetical order for each position (first, second, and third letter) across the terms in the series. Once the pattern is identified, we apply it to find the missing term.
A) ORV is the correct option because it follows the established pattern of increasing each letter's alphabetical position by 2 in each subsequent term.
The nature of the image formed by a spherical mirror can be determined by analyzing the sign and magnitude of the magnification. Magnification provides information about whether the image is real or virtual, erect or inverted, and enlarged or diminished.
Correct Option: A) Virtual, erect and diminished
To solve this problem, we need to apply two transformation rules to the letters of the word PAINTED: one for vowels and one for consonants. After transforming each letter, we will form a new word and then identify the letter at the third position from the left.
B) J is the letter in the third position from the left in the new group of letters.
This is a blood relations question where symbols represent relationships. We need to decode the given expression step-by-step to determine the relationship between M and T.
B) Mother's brother's wife's father. This matches our step-by-step deduction. M is the father of N, N is the wife of P, P is the brother of S, and S is the mother of T. Therefore, M is the father of N, who is the wife of P, who is the brother of S, who is the mother of T. So, M is T's mother's brother's wife's father.
The problem presents two pairs of letter groups (GTC : KWE and WFK : AIM) that follow a specific pattern. We need to identify which of the given options follows the same pattern. We will analyze the letter-to-letter relationships within the given pairs to deduce the pattern and then apply it to the options.
D) OZG : SCI
This pair follows the (+4, +3, +2) pattern. Therefore, option D is the correct answer.
To solve this problem, we will first define the initial dimensions and area of the garden. Then, we will calculate the new dimensions after the given percentage changes in length and breadth. Finally, we will determine the new area and compare it with the old area to find the percentage increase.
Let the original length of the rectangular garden be \(L\) and the original breadth be \(B\).
The original area of the garden, \(A_{\text{old}}\), is given by:
\[ A_{\text{old}} = L \times B \]The length is increased by 40%. So, the new length, \(L_{\text{new}}\), will be:
\[ L_{\text{new}} = L + 0.40L = 1.40L \]The breadth is decreased by 20%. So, the new breadth, \(B_{\text{new}}\), will be:
\[ B_{\text{new}} = B - 0.20B = 0.80B \]The new area of the garden, \(A_{\text{new}}\), is the product of the new length and new breadth:
\[ A_{\text{new}} = L_{\text{new}} \times B_{\text{new}} \]\[ A_{\text{new}} = (1.40L) \times (0.80B) \]\[ A_{\text{new}} = (1.40 \times 0.80) \times (L \times B) \]\[ A_{\text{new}} = 1.12 \times (L \times B) \]Since \(A_{\text{old}} = L \times B\), we can write:\[ A_{\text{new}} = 1.12 \times A_{\text{old}} \]The increase in area is \(A_{\text{new}} - A_{\text{old}}\).
\[ \text{Increase in Area} = 1.12 A_{\text{old}} - A_{\text{old}} = 0.12 A_{\text{old}} \]The percentage increase is calculated as:\[ \text{Percentage Increase} = \left( \frac{\text{Increase in Area}}{A_{\text{old}}} \right) \times 100\% \]\[ \text{Percentage Increase} = \left( \frac{0.12 A_{\text{old}}}{A_{\text{old}}} \right) \times 100\% \]\[ \text{Percentage Increase} = 0.12 \times 100\% \]\[ \text{Percentage Increase} = 12\% \]B) 12% is the correct answer. The new area is 12% more than the old area.
To find the equivalent resistance of resistors connected in parallel, we use a specific formula that relates the reciprocals of individual resistances to the reciprocal of the equivalent resistance. For two resistors, this formula can be simplified.
Identify the given resistances:
We are given two resistors, \(R_1 = 4 \, \Omega\) and \(R_2 = 6 \, \Omega\).
Recall the formula for equivalent resistance in a parallel circuit:
For resistors connected in parallel, the reciprocal of the equivalent resistance (\(R_{eq}\)) is the sum of the reciprocals of the individual resistances:
\[ \frac{1}{R_{eq}} = \frac{1}{R_1} + \frac{1}{R_2} \]Substitute the given values into the formula:
\[ \frac{1}{R_{eq}} = \frac{1}{4 \, \Omega} + \frac{1}{6 \, \Omega} \]Find a common denominator and add the fractions:
The least common multiple of 4 and 6 is 12.
\[ \frac{1}{R_{eq}} = \frac{3}{12 \, \Omega} + \frac{2}{12 \, \Omega} \]\[ \frac{1}{R_{eq}} = \frac{3 + 2}{12 \, \Omega} \]\[ \frac{1}{R_{eq}} = \frac{5}{12 \, \Omega} \]Calculate the equivalent resistance \(R_{eq}\):
To find \(R_{eq}\), take the reciprocal of the sum:
\[ R_{eq} = \frac{12}{5} \, \Omega \]\[ R_{eq} = 2.4 \, \Omega \]Correct Option: D) 2.4 ฮฉ