The problem asks us to find a set of numbers that follows the same relationship as the given sets: (41, 34, 24) and (63, 80, 23). We need to identify the pattern or rule connecting the three numbers in each given set.
Correct Option: B) (43, 40, 23)
The question asks about a specific provision sanctioned by the Charter Act of 1813. We need to recall the key features of this Act and identify which of the given options aligns with its provisions.
Correct Option: C) Introduction of western sciences
The problem requires us to find the discount percentage given the marked price, the percentage above cost price, and the profit percentage. We will first calculate the cost price, then the selling price using the profit percentage, and finally the discount percentage using the marked price and selling price.
The marked price (MP) is Rs. 668, which is 22% above the cost price (CP).
\[ \text{MP} = \text{CP} + 0.22 \times \text{CP} \]So,
\[ \text{MP} = \text{CP} (1 + 0.22) = 1.22 \times \text{CP} \]Given \(\text{MP} = 668\), we have:
\[ 668 = 1.22 \times \text{CP} \]\[ \text{CP} = \frac{668}{1.22} = 547.54098... \]\[ \text{CP} \approx \text{Rs. } 547.54 \]The profit percentage is 7% on the cost price.
\[ \text{Profit} = 0.07 \times \text{CP} \]\[ \text{SP} = \text{CP} + \text{Profit} = \text{CP} (1 + 0.07) = 1.07 \times \text{CP} \]Using the calculated CP:
\[ \text{SP} = 1.07 \times 547.54098 \]\[ \text{SP} = 585.86885... \]\[ \text{SP} \approx \text{Rs. } 585.87 \]The discount is given on the marked price.
\[ \text{Discount Amount} = \text{MP} - \text{SP} \]\[ \text{Discount Amount} = 668 - 585.86885 = 82.13115 \]\[ \text{Discount Percentage} = \frac{\text{Discount Amount}}{\text{MP}} \times 100 \]\[ \text{Discount Percentage} = \frac{82.13115}{668} \times 100 \]\[ \text{Discount Percentage} = 0.1229508... \times 100 \]\[ \text{Discount Percentage} \approx 12.295 \% \]Rounding 12.295% to two decimal places gives 12.30%.
Correct Option: B) 12.30%
The question asks for the primary reason roughage is included in a balanced human diet. We need to evaluate each option based on the known functions of dietary fiber (roughage) in the human body.
Based on this evaluation, the most accurate primary reason for including roughage in the diet is its role in digestion and preventing constipation.
Correct Option: B) It aids digestion and prevents constipation.
The question asks about the material used to create the famous 'Dancing Girl' statue from the Indus Valley Civilization. This is a factual question related to ancient Indian history and archaeology. Knowledge of the materials and technologies prevalent during the Indus Valley Civilization is key to answering this.
Correct Option: C) The 'Dancing Girl' statue, a renowned artifact from Mohenjo-Daro (Indus Valley Civilization), is famously made of bronze. This indicates the advanced metallurgical skills of the Harappan people, who were adept at alloying copper with other metals like tin to create bronze.
The question asks to identify which of the given urban areas was classified as a "Million Plus Urban Agglomeration City" according to the Census of India 2001. This requires knowledge of the population classifications used in the Indian Census and the specific cities that met the criteria in 2001.
C) Lucknow was indeed a Million Plus Urban Agglomeration City as per the Census of India 2001, with a population exceeding 2 million.
This is a logical reasoning problem involving sequencing events (exams) over a week. We need to deduce the exact schedule of exams for each person based on the given clues and then determine the number of people between U and C.
List the days of the week:
Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday
Place the confirmed exam:
"F has the exam on Thursday."
Schedule: _ _ _ F _ _ _
Use the clue about T:
"T has the exam on one of the days after F."
This means T can be on Friday, Saturday, or Sunday.
Use the clue about U, T, and D:
"U has the exam on one of the days after T but on one of the days before D."
This implies the sequence T, U, D. Since T is after F (Thursday), and there are only 3 days after F, the only possible arrangement for T, U, D is Friday, Saturday, Sunday respectively.
Schedule: _ _ _ F T U D
Remaining people and days:
People left: C, E, S
Days left: Monday, Tuesday, Wednesday
Use the clue about C, S, and E:
"C has the exam on one of the days after S and on one of the days before E."
This implies the sequence S, C, E. Since these three must occupy Monday, Tuesday, and Wednesday, the only possible arrangement is S on Monday, C on Tuesday, and E on Wednesday.
Final Schedule:
Monday: S
Tuesday: C
Wednesday: E
Thursday: F
Friday: T
Saturday: U
Sunday: D
Determine the number of people between U and C:
U is on Saturday and C is on Tuesday. The people between C (Tuesday) and U (Saturday) are E (Wednesday), F (Thursday), and T (Friday).
Count the people: There are 3 people (E, F, T) between U and C.
B) Three. As determined in the step-by-step solution, there are three people (E, F, T) who have their exams between U and C.
This problem requires us to substitute the given symbols with their corresponding mathematical operators and then evaluate each expression following the order of operations (BODMAS/PEMDAS) to find which one results in 50.
Given the symbol mappings:
We will evaluate each option:
Substitute the symbols:
\[ 24 - 4 \times 28 \div 12 + 6 \]Perform division first:
\[ 24 - 4 \times \frac{28}{12} + 6 = 24 - 4 \times \frac{7}{3} + 6 \]Perform multiplication:
\[ 24 - \frac{28}{3} + 6 \]Combine terms:
\[ 30 - \frac{28}{3} = \frac{90 - 28}{3} = \frac{62}{3} \approx 20.67 \]This is not 50.
Substitute the symbols:
\[ 24 \times 4 + 28 - 12 \div 6 \]Perform division first:
\[ 24 \times 4 + 28 - 2 \]Perform multiplication:
\[ 96 + 28 - 2 \]Perform addition and subtraction:
\[ 124 - 2 = 122 \]This is not 50.
Substitute the symbols:
\[ 24 \div 4 - 28 + 12 \times 6 \]Perform division and multiplication:
\[ 6 - 28 + 72 \]Perform addition and subtraction from left to right:
\[ -22 + 72 = 50 \]This is 50.
Substitute the symbols:
\[ 24 + 4 \div 28 \times 12 - 6 \]Perform division first:
\[ 24 + \frac{4}{28} \times 12 - 6 = 24 + \frac{1}{7} \times 12 - 6 \]Perform multiplication:
\[ 24 + \frac{12}{7} - 6 \]Combine terms:
\[ 18 + \frac{12}{7} = \frac{126 + 12}{7} = \frac{138}{7} \approx 19.71 \]This is not 50.
C) 24 P 4 S 28 R 12 Q 6 results in 50.
The question asks to identify the physicist who replaced Newtonian concepts of absolute space and absolute time with his theory of relativity. This requires knowledge of the history of physics and the key contributions of prominent scientists.
D) Albert Einstein — Albert Einstein, through his Special Theory of Relativity (1905) and General Theory of Relativity (1915), revolutionized physics by introducing the concepts of relative space and relative time, which are dependent on the observer's motion and gravitational fields, respectively. This directly replaced Newton's ideas of absolute space and absolute time.