The question asks for the year in which the Battle of Kalinga was fought, an event that significantly influenced Emperor Ashoka to adopt Buddhism. This is a direct factual recall question from ancient Indian history.
Correct Option: B) 261 BCE is the widely accepted historical date for the Battle of Kalinga. This battle was a turning point in Ashoka's life, leading him to renounce warfare and adopt Buddhism, promoting its principles of peace and non-violence (Dhamma).
This problem involves substituting given symbols with mathematical operators and then solving the resulting expression using the BODMAS/PEMDAS rule (Order of Operations).
The original equation is: \(19 \text{ B } 4 \text{ D } 7 \text{ B } 8 \text{ C } 32 \text{ D } 11 \text{ B } 2 = ?\)
Substituting the operators, we get:
\[ 19 \times 4 - 7 \times 8 + 32 - 11 \times 2 = ? \]BODMAS/PEMDAS stands for Brackets, Orders (powers/roots), Division, Multiplication, Addition, Subtraction. We perform operations in this order from left to right.
Perform all multiplications from left to right:
\[ 19 \times 4 = 76 \]\[ 7 \times 8 = 56 \]\[ 11 \times 2 = 22 \]Now, perform additions and subtractions from left to right:
\[ 76 - 56 = 20 \]\[ 20 + 32 = 52 \]\[ 52 - 22 = 30 \]C) 30 is the correct answer, as calculated by substituting the operators and following the BODMAS rule.
To find the average speed for the two-way journey, we need to calculate the total distance covered and the total time taken. The average speed is then the total distance divided by the total time.
Calculate the total distance:
Shanu walks 5 km to his office and then 5 km back home. So, the total distance is:
\[\text{Total Distance} = 5 \text{ km} + 5 \text{ km} = 10 \text{ km}\]Calculate the time taken for the morning journey:
Time taken to go to the office = 1 hour.
Calculate the time taken for the evening journey:
While returning, he takes 30 more minutes than the morning journey. So, the time taken is:
\[\text{Time (evening)} = 1 \text{ hour} + 30 \text{ minutes}\]Convert 30 minutes to hours:
\[30 \text{ minutes} = \frac{30}{60} \text{ hours} = 0.5 \text{ hours}\]So, the time taken for the evening journey is:
\[\text{Time (evening)} = 1 \text{ hour} + 0.5 \text{ hours} = 1.5 \text{ hours}\]Calculate the total time taken for the two-way journey:
\[\text{Total Time} = \text{Time (morning)} + \text{Time (evening)}\] \[\text{Total Time} = 1 \text{ hour} + 1.5 \text{ hours} = 2.5 \text{ hours}\]Calculate the average speed:
The formula for average speed is:
\[\text{Average Speed} = \frac{\text{Total Distance}}{\text{Total Time}}\] \[\text{Average Speed} = \frac{10 \text{ km}}{2.5 \text{ hours}}\] \[\text{Average Speed} = 4 \text{ km/hr}\]D) 4 — The total distance covered is 10 km, and the total time taken is 2.5 hours. Dividing the total distance by the total time gives an average speed of 4 km/hr.
To determine the percentage of profit or loss, we will first assume a cost price (CP) for the goods. Then, we will calculate the marked price (MP) based on the given percentage above CP. Finally, we will calculate the selling price (SP) after applying the discount on the marked price. The profit or loss percentage can then be found by comparing the SP with the CP.
The seller incurs a 4% loss.
C) 4% loss
The question provides two words, ROME and TURN, along with their numerical codes, 7245 and 5689. We need to identify the code for the letter R by comparing the common letters and common digits in both coded words.
Identify the given words and their codes:
We need to determine the numerical code representing the letter R.
Compare the letters in both words:
The letters in ROME are R, O, M and E.
The letters in TURN are T, U, R and N.
The only common letter in both words is R.
Compare the digits in both codes:
The digits in 7245 are 7, 2, 4 and 5.
The digits in 5689 are 5, 6, 8 and 9.
The only common digit in both codes is 5.
Identify the code for R:
Since R is the only common letter and 5 is the only common digit in both coded words, the letter R corresponds to the digit 5.
\[ R=5 \]Therefore, the code for R is 5.
Correct Option: B) 5 — The letter R appears in both ROME and TURN. Similarly, the digit 5 appears in both numerical codes, 7245 and 5689. Since R is the only common letter and 5 is the only common digit, R is coded as 5. Hence, Option B is the correct answer.
A) 9: This is incorrect because the digit 9 appears only in the code 5689, whereas R is present in both words.
C) 2: This is incorrect because the digit 2 appears only in the code 7245, whereas R appears in both words.
D) 7: This is incorrect because the digit 7 appears only in the code 7245, whereas the code for R must be common to both numerical codes.
The question asks for the key used to start a new line within a text box in MS PowerPoint. This is a fundamental function in most text-editing applications.
Correct Option: B) Enter is the correct key to press to start a new line while typing inside a text box in MS PowerPoint.
The problem involves properties of circles, specifically angles subtended by arcs, and properties of tangents from an external point. We will use the relationship between the angle subtended by an arc at the center and at any point on the circumference, and the property that the angle between two tangents from an external point is related to the angle subtended by the chord of contact at the center.
We are given that AB is a chord in the minor segment of a circle with center Q, and P is a point on the major arc AB. We are given \(\angle APB = 39^\circ\).
The angle subtended by an arc at the center is double the angle subtended by it at any point on the remaining part of the circle. Here, arc AB subtends \(\angle APB\) at point P on the major arc and \(\angle AQB\) at the center Q.
Therefore, \(\angle AQB = 2 \times \angle APB\).
Substituting the given value:
\[ \angle AQB = 2 \times 39^\circ = 78^\circ \]AD and BD are tangents drawn from an external point D to the circle. The radii to the points of tangency are perpendicular to the tangents. So, \(QA \perp AD\) and \(QB \perp BD\).
This means \(\angle QAD = 90^\circ\) and \(\angle QBD = 90^\circ\).
Consider the quadrilateral QADB. The sum of angles in a quadrilateral is \(360^\circ\).
So, \(\angle QAD + \angle ADB + \angle DBQ + \angle BQA = 360^\circ\).
Substituting the known angles:
\[ 90^\circ + \angle ADB + 90^\circ + 78^\circ = 360^\circ \] \[ 180^\circ + 78^\circ + \angle ADB = 360^\circ \] \[ 258^\circ + \angle ADB = 360^\circ \]Now, solve for \(\angle ADB\):
\[ \angle ADB = 360^\circ - 258^\circ \] \[ \angle ADB = 102^\circ \]C) 102° is the correct measure for \(\angle ADB\).
The problem asks us to identify a triad that follows the same pattern as the given triads. We need to analyze the letter positions in the alphabet for each letter in the given triads to find the underlying rule.
Both triads show a consistent pattern in the differences between the letter positions. The first triad has differences \(21, 5, 5\). The second triad has differences \(5, 5, 5\). It seems the pattern is that the difference between the letters in the first pair is different, but the differences in the second and third pairs are the same. More importantly, let's look at the progression between the pairs.
So, the pattern is that the first letter of each subsequent pair increases by 4, and the second letter of each subsequent pair also increases by 4 (cyclically for X to B).
This confirms the pattern: the first letter of each subsequent pair increases by 4, and the second letter of each subsequent pair also increases by 4.
This option follows the pattern.
Correct Option: B) WR-AV-EZ
This problem involves simple interest. We are given the amount (Principal + Interest) at two different time periods. We can use this information to find the simple interest earned over a specific period, then calculate the principal amount, and finally determine the rate of interest.
Let the Principal be \(P\) and the annual rate of interest be \(R\).
The amount after 2 years is ₹1,300. This means:
\[ P + \text{Simple Interest for 2 years} = 1300 \quad (1) \]The amount after 4 years is ₹2,100. This means:
\[ P + \text{Simple Interest for 4 years} = 2100 \quad (2) \]Since it's simple interest, the interest earned each year is constant. The difference in the amounts between 4 years and 2 years is the simple interest earned in \(4 - 2 = 2\) years.
\[ \text{Simple Interest for 2 years} = \text{Amount in 4 years} - \text{Amount in 2 years} \]\[ \text{Simple Interest for 2 years} = 2100 - 1300 = \text{₹}800 \]Now we know the simple interest for 2 years is ₹800. We can find the simple interest for 1 year:
\[ \text{Simple Interest for 1 year} = \frac{800}{2} = \text{₹}400 \]Substitute the simple interest for 2 years back into equation (1) to find the Principal \(P\):
\[ P + 800 = 1300 \]\[ P = 1300 - 800 = \text{₹}500 \]Now we have the Principal \(P = \text{₹}500\), the Simple Interest for 1 year \(SI = \text{₹}400\), and the time \(T = 1\) year. We can use the simple interest formula to find the rate of interest \(R\):
\[ SI = \frac{P \times R \times T}{100} \]\[ 400 = \frac{500 \times R \times 1}{100} \]\[ 400 = 5 \times R \]\[ R = \frac{400}{5} \]\[ R = 80\% \]A) 80% is the correct rate of interest per annum.
The question asks about the specific battle that led to Emperor Ashoka's conversion to Buddhism. This is a direct historical fact related to the Mauryan Empire and Ashoka's reign. We need to identify the battle known for its immense bloodshed and its profound impact on Ashoka's ideology and subsequent embrace of Buddhism.
Correct Option: C) The Battle of Kalinga (around 261 BCE) was a brutal war fought between the Mauryan Empire under Ashoka and the state of Kalinga (modern-day Odisha). The scale of destruction and loss of life in this battle had a profound impact on Ashoka. He was filled with remorse and disgust at the violence, which led him to abandon military conquest and embrace Buddhism, dedicating his life to spreading its teachings of peace and non-violence.