The question asks to identify the tribal leader who was deported to another country rather than executed during their revolt. This requires knowledge of the fate of prominent tribal leaders involved in various uprisings against British rule in India.
Tirot Sing (also spelled U Tirot Sing Syiem) was a Khasi chief who led a rebellion against the British in the 1830s. He was eventually captured in 1833 and deported to Dhaka (now in Bangladesh), where he died in captivity in 1835. He was not executed by the British.
Tilka Manjhi led the Paharia revolt in the late 18th century. He was captured in 1784 and publicly hanged in Bhagalpur.
Nilamber and Pitamber were brothers who led the Bhogta rebellion (part of the larger Chero uprising) in Palamu in 1857-58. They were captured and hanged by the British.
Sidhu and Kanhu Murmu were the leaders of the Santhal Rebellion of 1855-56. Both were captured and executed by the British.
Based on this information, Tirot Sing is the leader who was deported rather than executed.
C) Tirot Sing — He was a Khasi chief who led a rebellion against the British in the 1830s. After his capture in 1833, he was deported to Dhaka, where he died in captivity in 1835. He was not executed.
The problem presents an analogy based on letter clusters. We need to identify the pattern or relationship between the letters in the given pair (MRN) and apply the same logic to find the missing clusters (# and %). This usually involves analyzing the alphabetical positions of the letters or the operations (addition/subtraction) performed on their positions.
D) # = PUQ, % = EJF. The pattern is that each letter in the second cluster of a pair is obtained by subtracting 3 from the alphabetical position of the corresponding letter in the first cluster. For example, for PUQ : MRN:
Applying this to HMI to find %:
Thus, % = EJF.
The problem asks us to identify a triad that follows the same pattern as the two given triads. We need to analyze the letter positions in the alphabet for each letter in the given triads to find the underlying rule.
B) OJ-QM-TV — This option follows the pattern: First letters increase by +2, then +3. Second letters increase by +3, then +9.
To find the average earning per day, we need to sum up the earnings over all five days and then divide this total by the number of days.
The earnings are given for 5 days.
The formula for average is:
\[ \text{Average} = \frac{\text{Sum of all values}}{\text{Number of values}} \]In this case:
\[ \text{Average Earning} = \frac{\text{Total Earnings}}{\text{Number of Days}} \] \[ \text{Average Earning} = \frac{2500}{5} \] \[ \text{Average Earning} = 500 \text{ ₹} \]Correct Option: A) ₹500
To find the ratio of the two numbers, we first need to express them in terms of a third number. We can assume the third number to be 100 to simplify calculations, or use a variable. Then, we calculate the values of the two numbers based on the given percentages and form their ratio.
Let the third number be \(C\).
The first number, let's call it \(A\), is 47% more than the third number.
So, \(A = C + 47\% \text{ of } C\)
\[ A = C + \frac{47}{100}C = C \left(1 + \frac{47}{100}\right) = C \left(\frac{100+47}{100}\right) = \frac{147}{100}C \]The second number, let's call it \(B\), is 25% more than the third number.
So, \(B = C + 25\% \text{ of } C\)
\[ B = C + \frac{25}{100}C = C \left(1 + \frac{25}{100}\right) = C \left(\frac{100+25}{100}\right) = \frac{125}{100}C \]Now, we need to find the ratio of the two numbers, \(A : B\).
\[ A : B = \frac{147}{100}C : \frac{125}{100}C \]We can cancel out \(C\) and the common denominator \(100\):
\[ A : B = 147 : 125 \]D) 147 : 125 is the correct ratio of the two numbers.
This problem involves tracking movements in different directions. We can solve it by breaking down Barun's journey into horizontal (East-West) and vertical (North-South) components. We will calculate the net displacement in each direction from the starting point A to the final point P. Then, we can determine the shortest distance and direction needed to return to A.
C) 4 km to the south. As calculated, Point P is 4 km North of Point A. Therefore, to return to A, Barun must drive 4 km to the South.
This is a circular seating arrangement puzzle. We need to deduce the positions of seven people (Karuna, Jyoti, Shiv, Ram, Puran, Om, and Luv) sitting around a circular table, all facing the center. We will use the given clues to place them one by one and then determine who sits to the immediate left of Ram.
A) Luv sits to the immediate left of Ram.
The problem asks us to identify a sequence of numbers from the options that follows the same set of mathematical operations as given in two example sequences. We need to analyze the operations between consecutive numbers in the given sequences and then apply the identified pattern to the options.
C) 10 - 20 - 24 - 48
This option perfectly follows the identified pattern.
This problem involves analyzing logical statements and conclusions, a common type of question in competitive exams. We will use Venn diagrams to represent the relationships given in the statements and then evaluate each conclusion based on these diagrams.
D) Only conclusion (II) follows
Nirbhay can complete a piece of work alone in 19 days and Vismay can complete the same piece of work alone in 6 days. They started the work together, but Nirbhay had to leave 4 days before the completion of the work. In how many days will the work get completed?
5 \( \frac{13}{25} \) days
5 \( \frac{6}{25} \) days
5 \( \frac{8}{25} \) days
5 \( \frac{24}{25} \) days
This problem involves work and time. We need to calculate the individual work rates, then consider the scenario where one person leaves before completion. The key is to determine the amount of work done by each person and the total time taken.
Calculate individual work rates:
Define variables:
Determine the time each person worked:
Formulate the equation for total work:
The total work done is the sum of the work done by Nirbhay and Vismay.
\[ \left( \text{Nirbhay's work rate} \times \text{Days Nirbhay worked} \right) + \left( \text{Vismay's work rate} \times \text{Days Vismay worked} \right) = 1 \text{ (total work)} \] \[ \frac{1}{19} (T - 4) + \frac{1}{6} T = 1 \]Solve the equation for \( T \):
To eliminate the denominators, find the least common multiple (LCM) of 19 and 6, which is \( 19 \times 6 = 114 \).
Multiply the entire equation by 114:
\[ 6(T - 4) + 19T = 114 \]Distribute and simplify:
\[ 6T - 24 + 19T = 114 \] \[ 25T - 24 = 114 \]Add 24 to both sides:
\[ 25T = 114 + 24 \] \[ 25T = 138 \]Divide by 25:
\[ T = \frac{138}{25} \]Convert the improper fraction to a mixed number:
\[ T = 5 \frac{13}{25} \text{ days} \]