In △ABC, ∠A = 135°, CA = \(5\sqrt{2}\) cm and AB = 7 cm. E and F are the midpoints of sides AC and AB, respectively. The length of EF (in cm) is:
The altitude AD of a triangle ABC is 9 cm. If AB = 6\(\sqrt{3}\) cm and CD = 3\(\sqrt{3}\) cm, then what will be the measure of ∠A?
In △ABC, AD is a median. If points E, F and G are midpoints of AD, AE and DE, respectively, then what will be the area of △BFG?
\(\tfrac{1}{2}(\text{Area }\triangle ABC)\)
\(\tfrac{1}{8}(\text{Area }\triangle ABC)\)
\(\tfrac{1}{2}(\text{Area }\triangle BGC)\)
Find the area (in cm2) and the diameter (in cm), respectively, of a circle whose circumference is 40π cm?
What is the area (in m2, up to 1 place of decimal) of an equilateral triangular field of sides 8.5 m?
\(\dfrac{18.1}{\sqrt{3}}\)
\(18.1\sqrt{3}\)
\(\dfrac{72.25}{\sqrt{3}}\)
\(72.25\sqrt{3}\)
The centroid of an equilateral triangle △ABC is O. If AB = 27 cm, then the length of AO is:
\(9\sqrt{3}\ \text{cm}\)
\(6\sqrt{3}\ \text{cm}\)
\(7\sqrt{3}\ \text{cm}\)
\(8\sqrt{3}\ \text{cm}\)