Reversible and Irreversible Processes NEET Questions

Reversible and Irreversible Processes MCQ Questions

7.
The key reason why a reversible process cannot be achieved in practice is:
A.
There are no ideal gases in the real world
B.
Temperature differences cannot be maintained in practice
C.
Dissipative effects like friction and viscosity are always present and cannot be completely eliminated
D.
Pressure cannot be kept exactly constant in real processes
ANSWER :
C. Dissipative effects like friction and viscosity are always present and cannot be completely eliminated
8.
According to NCERT, irreversibility arises from two main causes. These are:
A.
(1) Processes that take the system to non-equilibrium states; (2) Dissipative effects like friction and viscosity
B.
Chemical reactions and nuclear reactions only
C.
High temperature and high pressure
D.
Large volume changes and large pressure changes
ANSWER :
A. (1) Processes that take the system to non-equilibrium states; (2) Dissipative effects like friction and viscosity
9.
A free expansion of gas is irreversible because:
A.
The gas does too much work on the surroundings
B.
The gas passes through non-equilibrium states — pressure and temperature are not uniform during expansion
C.
Heat is lost to the surroundings
D.
The gas loses its chemical composition
ANSWER :
B. The gas passes through non-equilibrium states — pressure and temperature are not uniform during expansion
10.
A moving body comes to a stop due to friction, losing mechanical energy as heat. This process is irreversible because:
A.
The body becomes hotter than the floor
B.
Friction generates electricity
C.
Converting ALL that heat back entirely into kinetic energy of the body would violate the Second Law (Kelvin-Planck statement)
D.
The body dissolves in the floor
ANSWER :
C. Converting ALL that heat back entirely into kinetic energy of the body would violate the Second Law (Kelvin-Planck statement)
11.
A rotating blade in a liquid comes to rest due to viscosity. The irreversibility here arises from:
A.
The blade losing mass
B.
Viscous dissipation converting ordered rotational KE to disordered thermal energy (internal energy of liquid) — cannot be spontaneously reversed
C.
Surface tension of the liquid
D.
Quasi-static slowing of the blade
ANSWER :
B. Viscous dissipation converting ordered rotational KE to disordered thermal energy (internal energy of liquid) — cannot be spontaneously reversed
12.
The stirring of a liquid in thermal contact with a reservoir converts work to heat, increasing the reservoir's internal energy. This process is irreversible because:
A.
The liquid changes composition
B.
The temperature of the reservoir drops permanently
C.
Stirring removes molecules from the liquid
D.
To reverse it would require extracting heat from the reservoir and converting it entirely into the original stirring work — violating the Kelvin-Planck statement
ANSWER :
D. To reverse it would require extracting heat from the reservoir and converting it entirely into the original stirring work — violating the Kelvin-Planck statement