The question asks to identify the mode of reproduction used in agricultural practices like layering and grafting for plants such as sugarcane, roses, and grapes. These methods involve using parts of a parent plant to grow new plants, which is a characteristic of asexual reproduction.
D) Vegetative propagation — This is a form of asexual reproduction in plants where new plants are produced from vegetative parts of the parent plant, such as stems (as in layering, grafting, sugarcane cuttings), roots, or leaves. This method ensures that the new plants are genetically identical to the parent, preserving desirable traits, which is crucial in agriculture for crops like roses, grapes, and sugarcane.
To find the total distance travelled by Sumit, we need to add all the individual distances travelled by different modes of transport. It is important to convert all distances to a common unit (either kilometers or meters) before adding them, or to add kilometers and meters separately and then carry over if meters exceed 1000.
Correct Option: D) 27 km 940 m
The problem asks us to identify the letter cluster pair that does not follow the same pattern as the others, based on the English alphabetical order. We need to find the relationship between the letters within each cluster (e.g., YD) and between the two clusters in each pair (e.g., YD and WD).
From the analysis, we can see a consistent pattern in options B, C, and D:
Let's re-examine Option A based on this combined pattern:
Now let's look at the relationship between YD and WD as a pair:
Comparing this to the other options:
Option A (YD – WD) does not follow either of these patterns. The internal difference in YD and WD is not +2. The difference between Y and W is -2, and between D and D is 0, which is not +5.
A) YD – WD is the odd one out. In this pair, the relationship between Y and D, and W and D, is not that the second letter is two positions after the first. Also, the relationship between Y and W, and D and D, is not that the second cluster's letters are five positions after the first cluster's letters.
The question asks about the main focus of the pavilions at the India Art, Architecture, and Design Biennale in 2024. To answer this, one needs to recall the stated objectives or themes of the event for that specific year.
Correct Option: C) Contemporary art and innovative designs — The India Art, Architecture, and Design Biennale, especially in its recent editions like 2024, emphasizes showcasing cutting-edge contemporary art alongside innovative designs across various disciplines. This includes exploring new materials, technologies, and conceptual frameworks while often drawing inspiration from India's rich artistic and architectural heritage.
The problem asks us to identify the letter cluster pair that does not follow the same pattern as the others, based on the English alphabetical order. We need to find the relationship between the letters within each pair and between the two letters of the cluster.
A) LH – QM. This pair follows a \((+5, +5)\) pattern, while the other three pairs follow a \((+2, +2)\) pattern.
The question asks about the properties of angles formed when two parallel lines are intersected by a transversal. We need to identify the correct statements regarding these angles.
C) a and d
Since both 'a' and 'd' are true, option C, which states "a and d", is the correct answer.
To solve this problem, we need to establish a relationship between A's salary and B's salary based on the given percentage. Then, we will calculate the percentage by which B's salary is more than A's salary using A's salary as the base.
Let B's salary be \(B\). Since A's salary is 20% less than B's salary, A's salary (\(A\)) can be expressed as:
\[ A = B - 0.20B = 0.80B \]Now, we need to find by what percentage B's salary is more than A's salary. First, find the difference between B's salary and A's salary:
\[ \text{Difference} = B - A \]Substitute the expression for \(A\) from step 1 into the difference equation:
\[ \text{Difference} = B - 0.80B = 0.20B \]To find the percentage by which B's salary is more than A's salary, we need to divide this difference by A's salary and multiply by 100. A's salary is the reference point for this comparison.
\[ \text{Percentage more} = \frac{\text{Difference}}{\text{A's salary}} \times 100 \]Substitute the values from steps 1 and 3:
\[ \text{Percentage more} = \frac{0.20B}{0.80B} \times 100 \]Simplify the expression:
\[ \text{Percentage more} = \frac{0.20}{0.80} \times 100 = \frac{1}{4} \times 100 = 25\% \]Therefore, B's salary is 25% more than A's salary.
C) 25% is the correct answer, as calculated above.
A) 20% — This is incorrect. 20% is the percentage by which A's salary is less than B's salary. When the base for comparison changes (from B's salary to A's salary), the percentage also changes.
B) 17% — This value is not derived from the given information through standard percentage calculations.
D) 15% — This value is also not derived from the given information through standard percentage calculations.
In a row of people, all facing north, Bunty is 8th from the left end. Sneha is 15th from the left end. Sneha is exactly between Bunty and Nupur. If Nupur is 7th from the right end of the line, how many people are there in the row?
The problem involves finding the total number of people in a row based on the positions of three individuals: Bunty, Sneha, and Nupur. We will use their given positions from the left and right ends, and the information that Sneha is exactly between Bunty and Nupur, to determine the total number of people.
B) 28
The value of (256)0.16 × (256)0.09 is:
To solve this problem, we need to use the laws of exponents. Specifically, the rule \(a^m \times a^n = a^{m+n}\) will be applied. After combining the exponents, we will simplify the base number to its prime factors to easily calculate the final value.
The given expression is \((256)^{0.16} \times (256)^{0.09}\).
When multiplying terms with the same base, we add their exponents. The rule is \(a^m \times a^n = a^{m+n}\).
Here, \(a = 256\), \(m = 0.16\), and \(n = 0.09\).
So, we have:
\[ (256)^{0.16} \times (256)^{0.09} = (256)^{0.16 + 0.09} \]So the expression becomes:
\[ (256)^{0.25} \]We know that \[0.25 = \frac{25}{100} = \frac{1}{4}\].
Thus, the expression is:
\[ (256)^{1/4} \]We need to find the fourth root of 256. We can do this by finding the prime factorization of 256 or by recognizing powers of 2.
So, \(256 = 2^8\).
Now, substitute \(2^8\) back into the expression:
\[ (2^8)^{1/4} \]Using the exponent rule \((a^m)^n = a^{m \times n}\):
\[ 2^{8 \times (1/4)} = 2^{8/4} = 2^2 \]Finally, calculate the value:
\[ 2^2 = 4 \]Correct Option: D) 4
We are given that the marked price of an article is 50% above its cost price, and the marked price is ₹1,500. We need to find the cost price. We can set up an equation relating the marked price, cost price, and the percentage increase.
The article is marked at 50% above its cost price. This can be expressed as:
\[ MP = CP + 50\% \text{ of } CP \]Which simplifies to:
\[ MP = CP + \frac{50}{100} \times CP \] \[ MP = CP + 0.50 \times CP \] \[ MP = 1.50 \times CP \]We are given that the Marked Price (\(MP\)) is ₹1,500. Substitute this into the equation:
\[ 1500 = 1.50 \times CP \]To find \(CP\), divide both sides by 1.50:
\[ CP = \frac{1500}{1.50} \] \[ CP = \frac{1500}{\frac{3}{2}} \] \[ CP = 1500 \times \frac{2}{3} \] \[ CP = 500 \times 2 \] \[ CP = 1000 \]So, the cost price of the article is ₹1,000.
Correct Option: C) ₹1,000