The question asks to identify which substance is NOT stored in the vacuole of plant cells. We need to recall the primary functions and contents of plant cell vacuoles.
Correct Option: A) starch grains
The question asks to identify the substance with the lowest pH value among the given options. pH is a measure of how acidic or basic a solution is. A lower pH value indicates a higher acidity.
Correct Option: D) Gastric juice has the lowest pH value, typically ranging from 1.0 to 3.5, making it the most acidic among the given choices.
The problem requires us to transform the letters of the word GRAVITY based on specific rules: consonants change to the preceding letter, and vowels change to the succeeding letter. After this transformation, we need to count the number of consonants in the new group of letters.
A) Six. As calculated in the step-by-step explanation, there are 6 consonants (F, Q, B, J, S, X) in the new group of letters.
The question asks about the type of asexual reproduction exhibited by the malarial parasite. We need to recall the life cycle and reproductive strategies of Plasmodium (the malarial parasite) to identify the correct mode of asexual reproduction.
Correct Option: D) Multiple fission. The malarial parasite (Plasmodium) reproduces asexually in its human host through multiple fission, a process called schizogony, where one parent cell gives rise to many daughter cells simultaneously.
The question asks to identify the statement that is NOT a characteristic feature of epithelial tissue. We need to evaluate each option against the known properties of epithelial tissues.
Correct Option: D) Separated from the underlying tissue by a cellular, non-fibrous basement membrane
This statement is incorrect because the basement membrane is acellular and fibrous, not cellular and non-fibrous.
To evaluate the given expression, we need to follow the order of operations, commonly remembered by the acronym PEMDAS/BODMAS. This rule dictates the sequence in which mathematical operations should be performed: Parentheses/Brackets, Exponents/Orders, Multiplication and Division (from left to right), and Addition and Subtraction (from left to right).
Thus, the value of the expression \(19 - 20 \div 4\) is \(14\).
Correct Option: D) 14
The problem involves dividing an amount in a given ratio and then using the difference between the parts to find the actual difference in amounts. We will represent the parts using a common multiplier and then set up an equation based on the given information.
Let the two parts of the amount be \(4x\) and \(7x\), where \(x\) is a common multiplier. This is because the amount is divided in the ratio \(4:7\).
According to the problem statement, the second part is ₹6 more than the first part. So, we can write the equation:
\[ 7x = 4x + 6 \]Now, solve for \(x\):
\[ 7x - 4x = 6 \]\[ 3x = 6 \]\[ x = \frac{6}{3} \]\[ x = 2 \]The first part is \(4x = 4 \times 2 = \text{₹}8\).
The second part is \(7x = 7 \times 2 = \text{₹}14\).
The question asks for the difference in amount between the two friends. This is the difference between the second part and the first part:
\[ \text{Difference} = 7x - 4x = 3x \]Substitute the value of \(x\) into the difference:
\[ \text{Difference} = 3 \times 2 = \text{₹}6 \]B) ₹6 — The difference between the two parts is \(7x - 4x = 3x\). Since \(x=2\), the difference is \(3 \times 2 = \text{₹}6\).
To solve this problem, we need to calculate two percentages: 50% of 60 and 30% of 40. After finding these two values, we will subtract the smaller value from the larger one to find out by how much the first value is greater than the second.
To find a percentage of a number, we convert the percentage to a decimal or a fraction and then multiply it by the number.
\[ 50\% \text{ of } 60 = \frac{50}{100} \times 60 \]\[ = \frac{1}{2} \times 60 \]\[ = 30 \]Similarly, we calculate 30% of 40.
\[ 30\% \text{ of } 40 = \frac{30}{100} \times 40 \]\[ = \frac{3}{10} \times 40 \]\[ = 3 \times 4 \]\[ = 12 \]Now, we need to find out by how much 30 is greater than 12. We do this by subtracting 12 from 30.
\[ \text{Difference} = 30 - 12 \]\[ = 18 \]Thus, 50% of 60 is 18 greater than 30% of 40.
B) 18 is the correct answer because 50% of 60 is 30, and 30% of 40 is 12. The difference between these two values is \(30 - 12 = 18\).
Power of a lens of focal length 'f' is directly proportional to _______.
The question asks about the relationship between the power of a lens and its focal length. We need to recall the definition of the power of a lens and its formula.
A) \( \frac{1}{f} \) — This is correct because the power of a lens is defined as the reciprocal of its focal length. Therefore, power is directly proportional to \( \frac{1}{f} \).
The resistance of a conductor of length 'L' and cross-section area 'A' is directly proportional to _______.
The resistance of a conductor depends on its material properties and its physical dimensions. We need to recall the formula for electrical resistance in terms of length and cross-sectional area to determine the correct proportionality.
The electrical resistance (\(R\)) of a conductor is a measure of its opposition to the flow of electric current. It is determined by the material of the conductor and its geometry.
The formula for the resistance of a conductor is given by:
\[ R = \rho \frac{L}{A} \]Where:
From this formula, we can see that the resistance \(R\) is directly proportional to the length \(L\) and inversely proportional to the cross-sectional area \(A\).
Therefore, \(R\) is directly proportional to the ratio \( \frac{L}{A} \).
C) \( \frac{L}{A} \) — The resistance of a conductor is directly proportional to its length and inversely proportional to its cross-sectional area, meaning it is directly proportional to the ratio \( \frac{L}{A} \).