This question tests knowledge of basic plant reproduction, specifically the different types of pollination. Understanding the definitions of self-pollination and cross-pollination is key to answering this question.
D) self-pollination, cross pollination — This option correctly identifies self-pollination as the transfer of pollen within the same flower and cross-pollination as the transfer of pollen from one flower to another.
This is a coding-decoding problem where we need to find the code for a specific word by comparing common words and their codes across different given statements.
Thus, 'tiger' is written as 'hi'.
D) hi — As derived, by eliminating the codes for 'is', 'the', and 'king' from the first statement, 'tiger' is coded as 'hi'.
The question asks to identify the type of chemical reaction characterized by the exchange of ions between reactants. We need to recall the definitions of the different types of chemical reactions provided in the options and determine which one fits this description.
Correct Option: B) Double displacement reaction is the type of chemical reaction that involves the exchange of ions between the reactants.
To evaluate the given expression, we need to follow the order of operations, often remembered by the acronym PEMDAS/BODMAS. This rule dictates the sequence in which mathematical operations should be performed: Parentheses/Brackets, Exponents/Orders, Multiplication and Division (from left to right), Addition and Subtraction (from left to right).
Correct Option: C) 12
In triangle ABC, \(\overline{AB}\) = 6 m, \(\overline{BC}\) = 8 m, and \(\overline{AC}\) = 10 m. In triangle PRQ, \(\overline{PR}\) = 8 m, \(\overline{PQ}\) = 10 m, and \(\overline{RQ}\) = 6 m. Which of the following is a correct order of congruency?
â–³BCA congruent to â–³RPQ
â–³ABC congruent to â–³RPQ
â–³BAC congruent to â–³RPQ
â–³CBA congruent to â–³RPQ
To determine the correct order of congruency between two triangles, we need to match their corresponding sides and angles. Congruency means that all corresponding sides and all corresponding angles are equal. The Side-Side-Side (SSS) congruency criterion states that if three sides of one triangle are equal to three corresponding sides of another triangle, then the triangles are congruent.
We need to find a correspondence between the vertices such that the corresponding sides are equal.
Based on the matching vertices:
Therefore, â–³ABC is congruent to â–³RQP. If we write â–³BCA, then the corresponding triangle would be â–³QPR.
Let's re-evaluate based on the options provided. We need to match the order of vertices carefully.
Thus, â–³BCA is congruent to â–³RPQ.
A) â–³BCA congruent to â–³RPQ
Let's verify this option:
Since all corresponding sides are equal, the congruency â–³BCA \(\cong\) â–³RPQ is correct by SSS criterion.
The problem asks us to identify a pair of letter sets that follows the same pattern as the two given pairs: ARH : YOJ and SFP : QCR. We need to analyze the positional differences of the letters in the English alphabet for each pair to find the underlying rule.
Correct Option: D) WLL : UIN
The question asks about the deployment locations of indigenously developed Param Rudra Supercomputers in September 2024. This requires knowledge of recent developments in India's supercomputing infrastructure, specifically regarding the Param series developed by C-DAC.
B) Pune, Delhi and Kolkata are the correct locations where the indigenously developed Param Rudra Supercomputers were deployed in September 2024. These deployments were part of strengthening India's supercomputing capabilities for various applications, including weather forecasting and scientific research.
The question asks about the plane of cell division in organisms like Amoeba. This relates to the process of binary fission, a type of asexual reproduction. Understanding the characteristics of Amoeba's structure and how it divides is key to answering this question.
Therefore, due to its irregular and constantly changing shape, Amoeba's cell division can occur in any plane.
Correct Option: A) any plane — Amoeba lacks a definite shape and symmetry, allowing its binary fission to occur along any plane.
A dishonest shopkeeper claimed to have sold an item at ₹23/kg, which cost him ₹25/kg. However, by using faulty weights, he gave only 600 gm instead of 1 kg. What is his total percentage profit or loss?
23% loss
20% loss
62 \( \frac{1}{2} \) % profit
53 \( \frac{1}{3} \) % profit
This problem involves a dishonest shopkeeper who manipulates both the selling price and the weight of the item. To find the total percentage profit or loss, we need to calculate the actual cost price and the actual selling price for a given quantity of goods.
The shopkeeper bought the item at ₹25/kg.
\[ \text{CP for 1 kg} = \text{₹}25 \]The shopkeeper claimed to sell the item at ₹23/kg.
\[ \text{Claimed SP for 1 kg} = \text{₹}23 \]Instead of 1 kg (1000 gm), the shopkeeper gives only 600 gm.
This means that for the money he charges for 1 kg, he actually sells only 600 gm.
Let's consider the transaction from the shopkeeper's perspective for the quantity he actually sells.
He sells 600 gm for ₹23 (which is the price he charges for 1 kg).
The cost price for the 600 gm he actually sells is:
\[ \text{CP for 600 gm} = \frac{\text{₹}25}{\text{1000 gm}} \times \text{600 gm} = \text{₹}15 \]Actual Selling Price (SP) for 600 gm (what he charges for 1 kg) = ₹23
Actual Cost Price (CP) for 600 gm (what he paid for that quantity) = ₹15
Since SP > CP, there is a profit.
\[ \text{Profit} = \text{SP} - \text{CP} = \text{₹}23 - \text{₹}15 = \text{₹}8 \]Percentage profit is calculated on the cost price.
\[ \text{Percentage Profit} = \frac{\text{Profit}}{\text{CP}} \times 100\% \] \[ \text{Percentage Profit} = \frac{\text{₹}8}{\text{₹}15} \times 100\% \] \[ \text{Percentage Profit} = \frac{800}{15}\% = \frac{160}{3}\% \] \[ \text{Percentage Profit} = 53 \frac{1}{3}\% \]D) 53 \( \frac{1}{3} \) % profit
The problem asks us to find the value of 'n' given the Least Common Multiple (LCM) and Highest Common Factor (HCF) of 27 and 'n'. We will use the fundamental relationship between two numbers, their LCM, and their HCF: the product of two numbers is equal to the product of their LCM and HCF.
We are given two numbers, one of which is 27 and the other is 'n'.
For any two positive integers \(a\) and \(b\), the product of the numbers is equal to the product of their LCM and HCF.
\[ a \times b = \text{LCM}(a, b) \times \text{HCF}(a, b) \]Substitute \(a = 27\), \(b = n\), \(\text{LCM}(27, n) = 54\), and \(\text{HCF}(27, n) = 9\) into the formula:
\[ 27 \times n = 54 \times 9 \]Now, we need to isolate 'n' by dividing both sides of the equation by 27:
\[ n = \frac{54 \times 9}{27} \]We can simplify the expression:
\[ n = \frac{54}{27} \times 9 \]\[ n = 2 \times 9 \]\[ n = 18 \]B) 18 — The calculation shows that \(n = 18\).