The question asks to identify the zone of the Great Indian Plains characterized by high humidity and marshy conditions. This requires knowledge of the distinct features of different physiographic divisions of the Northern Plains of India.
Correct Option: D) The Terai belt is located south of the Bhabar region. In this zone, the streams that disappeared in the Bhabar re-emerge, creating a wet, marshy, and thickly forested area with high humidity, making it suitable for wildlife and dense vegetation.
The problem involves simple interest. We are given the amount after 3 years, the rate of interest, and the time. We need to find the simple interest for 1 year on the original sum. First, we will calculate the principal amount. Then, we will use the principal to find the simple interest for 1 year.
C) 600
This is a syllogism problem. We need to analyze the given statements and determine which conclusions logically follow. We can use Venn diagrams or logical deductions to represent the relationships between the categories (birds, omnivores, lions, reptiles).
Since both conclusion (I) and conclusion (II) logically follow from the given statements, the correct option is A.
A) Both conclusions (I) and (II) follow.
As explained in the step-by-step analysis, both conclusions are direct logical deductions from the given statements.
This is a logical reasoning problem involving arrangement based on given conditions. We need to determine the exam schedule for seven people (P, Q, R, S, T, U, V) over seven days of a week (Monday to Sunday) and then find the number of people between S and R.
Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday.
This means V must have the exam on Monday.
| Day | Person |
|---|---|
| Monday | V |
| Tuesday | |
| Wednesday | |
| Thursday | |
| Friday | |
| Saturday | |
| Sunday |
If Q is immediately before R, they occupy two consecutive slots (Q, R).
If there are four people between P and R, it means there are \(4+2 = 6\) slots between P and Q, or P and R. This implies P and R are quite far apart. Since there are only 7 days, P and R must be at the extreme ends with 4 people in between. The only way to fit 4 people between P and R is if P is on Tuesday and R is on Sunday, or vice-versa. However, V is on Monday, so P cannot be on Monday.
Let's consider the sequence: P _ _ _ _ R. This requires 6 days. Since Q is immediately before R, the sequence becomes P _ _ _ _ Q R. This requires 7 days. Given V is on Monday, this means P must be on Tuesday, and Q and R must be on Saturday and Sunday respectively.
| Day | Person |
|---|---|
| Monday | V |
| Tuesday | P |
| Wednesday | |
| Thursday | |
| Friday | |
| Saturday | Q |
| Sunday | R |
This means the sequence is S, T, U. These three must occupy the remaining three consecutive slots: Wednesday, Thursday, Friday.
| Day | Person |
|---|---|
| Monday | V |
| Tuesday | P |
| Wednesday | S |
| Thursday | T |
| Friday | U |
| Saturday | Q |
| Sunday | R |
From the final arrangement:
The people between S and R are T (Thursday), U (Friday), and Q (Saturday).
There are 3 people between S and R.
A) Three
To find the percentage gain or loss, we need to determine the cost price (CP), marked price (MP), and selling price (SP). We'll assume a convenient cost price to simplify calculations, then calculate the marked price based on the given markup percentage, and finally the selling price after applying the discount. From the CP and SP, we can find the gain or loss percentage.
Let the Cost Price (CP) of the goods be \(₹100\).
The salesman marks his goods 84% above the cost price.
\[ \text{Markup} = 84\% \text{ of CP} = \frac{84}{100} \times 100 = ₹84 \]\[ \text{Marked Price (MP)} = \text{CP} + \text{Markup} = 100 + 84 = ₹184 \]A discount of 50% is given on the marked price.
\[ \text{Discount Amount} = 50\% \text{ of MP} = \frac{50}{100} \times 184 = ₹92 \]\[ \text{Selling Price (SP)} = \text{MP} - \text{Discount Amount} = 184 - 92 = ₹92 \]Compare the Selling Price (SP) with the Cost Price (CP).
Here, \(\text{CP} = ₹100\) and \(\text{SP} = ₹92\).
Since \(\text{SP} < \text{CP}\), there is a loss.
\[ \text{Loss} = \text{CP} - \text{SP} = 100 - 92 = ₹8 \]The percentage loss is calculated with respect to the Cost Price.
\[ \text{Percentage Loss} = \frac{\text{Loss}}{\text{CP}} \times 100\% \]\[ \text{Percentage Loss} = \frac{8}{100} \times 100\% = 8\% \]Thus, the salesman incurs an 8% loss.
C) 8% loss
The question asks to identify the incorrect statement regarding the periodic trend of metallic character. We need to recall how metallic character changes across periods and down groups in the periodic table.
B) Metallic character increases across a period from left to right. This statement is incorrect. As explained in step 2, metallic character decreases across a period from left to right due to increasing effective nuclear charge and decreasing atomic size, which makes it harder to lose electrons.
This is a logical reasoning problem involving scheduling. We need to determine the exam schedule for seven people (P, Q, R, S, T, U, V) over seven days of a week (Monday to Sunday) based on the given clues. We will build a table representing the days and assign people to them step-by-step.
List the days of the week:
Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday
Use the direct information:
"T has an exam on Friday."
Schedule so far:
Monday: ?
Tuesday: ?
Wednesday: ?
Thursday: ?
Friday: T
Saturday: ?
Sunday: ?
Use the information about P and U:
"Exactly 3 people have an exam between P and U, neither of whom has an exam on Sunday."
This means P and U cannot be on Sunday. Also, if P is on Monday, U must be on Friday (3 people in between: Tue, Wed, Thu). If P is on Tuesday, U must be on Saturday. If P is on Wednesday, U must be on Sunday (not allowed). If P is on Thursday, U must be on Monday (not allowed as it would mean U is before P, but the 'between' count works both ways). However, we know T is on Friday, so P cannot be on Monday (as U would then be on Friday).
Let's consider the possible pairs for (P, U) or (U, P) with 3 people in between, avoiding Sunday for P and U:
Case 1: P on Tuesday, U on Saturday (3 people: Wed, Thu, Fri)
Case 2: U on Tuesday, P on Saturday (3 people: Wed, Thu, Fri)
Use the information about V and U:
"V has an exam immediately before U."
This means V and U must be consecutive days, with V preceding U.
Combine V-U with P-U information:
If U is on Saturday (from step 3), then V must be on Friday. But T is already on Friday. So, Case 1 (P on Tuesday, U on Saturday) and Case 2 (U on Tuesday, P on Saturday) are not possible if V is immediately before U and T is on Friday.
Let's re-evaluate the "exactly 3 people between P and U" condition. It means P and U are 4 days apart. For example, if P is on Monday, U is on Friday. If U is on Monday, P is on Friday.
Given T is on Friday, neither P nor U can be on Friday. This eliminates P on Monday (U on Friday) and U on Monday (P on Friday).
Let's list the days and mark T on Friday:
| Day | Person |
|---|---|
| Monday | |
| Tuesday | |
| Wednesday | |
| Thursday | |
| Friday | T |
| Saturday | |
| Sunday |
Now, consider "V has an exam immediately before U". This means (V, U) is a block. U cannot be on Sunday. P cannot be on Sunday.
Possible (V, U) blocks (U not on Sunday):
(Mon, Tue)
(Tue, Wed)
(Wed, Thu)
(Thu, Fri) - Not possible as T is on Friday.
(Sat, Sun) - Not possible as U cannot be on Sunday.
So, (V, U) can be (Mon, Tue), (Tue, Wed), or (Wed, Thu).
Now let's combine with "Exactly 3 people between P and U".
If (V, U) is (Mon, Tue):
V = Monday, U = Tuesday.
Then P must be 4 days after U (Tuesday + 4 days = Saturday) or 4 days before U (Tuesday - 4 days = Thursday of previous week, not possible).
So, P = Saturday. (3 people between U and P: Wed, Thu, Fri).
Schedule:
Monday: V
Tuesday: U
Wednesday: ?
Thursday: ?
Friday: T
Saturday: P
Sunday: ?
This schedule is consistent so far.
If (V, U) is (Tue, Wed):
V = Tuesday, U = Wednesday.
P must be 4 days after U (Wednesday + 4 days = Sunday). But P cannot be on Sunday. So this case is not possible.
If (V, U) is (Wed, Thu):
V = Wednesday, U = Thursday.
P must be 4 days after U (Thursday + 4 days = Monday of next week, not possible) or 4 days before U (Thursday - 4 days = Sunday). But P cannot be on Sunday. So this case is not possible.
Therefore, the only valid arrangement for V, U, P, and T is:
| Day | Person |
|---|---|
| Monday | V |
| Tuesday | U |
| Wednesday | |
| Thursday | |
| Friday | T |
| Saturday | P |
| Sunday |
Use the information about S and Q:
"S has an exam immediately after Q."
This means (Q, S) is a block of consecutive days. The remaining empty slots are Wednesday and Thursday, and Sunday.
The only consecutive empty slots are Wednesday and Thursday.
So, Q = Wednesday, S = Thursday.
Fill in the remaining person:
The only person left is R, and the only day left is Sunday.
So, R = Sunday.
Final Schedule:
| Day | Person |
|---|---|
| Monday | V |
| Tuesday | U |
| Wednesday | Q |
| Thursday | S |
| Friday | T |
| Saturday | P |
| Sunday | R |
Answer the question:
"How many people have an exam after S?"
S has an exam on Thursday. The people after S are T (Friday), P (Saturday), and R (Sunday).
There are 3 people after S.
A) 3
The question asks to identify the first woman officer appointed as the Director General, Armed Forces Medical Services (DGAFMS) in October 2024. This is a current affairs knowledge-based question.
C) Arti Sarin — Air Marshal Arti Sarin has been appointed as the Director General, Armed Forces Medical Services (DGAFMS), making her the first woman officer to hold this prestigious position. This appointment took place in October 2024, marking a significant milestone for women in the Indian Armed Forces.
To solve this number series problem, we need to identify the pattern or the rule governing the sequence of numbers. We will look for differences between consecutive terms to find a common arithmetic or geometric progression, or a pattern in the differences themselves.
A) 220 is the correct option because it fits the established pattern where the difference between consecutive terms decreases by 10 each time.