The average of eight numbers is 80. Find the least number if it is \( \frac{1}{16} \) of the sum of the numbers.
By how much is 60% of 40 greater than \( \frac{2}{5} \) of 55?
Simplify: \(\frac{\cot(\theta)}{\mathrm{cosec} (\theta)+1}+\frac{\mathrm{cosec} (\theta)+1}{\cot(\theta)}\)