The value of
is:
If x4 − 142x2 + 1 = 0, then the value of \(x^{3} + \dfrac{1}{x^{3}}\) is:
Given that (2x + y)3 - (x + 2y)3 = (x - y) [A(x2 + y2) + Bxy], the value of (2A - B) is:
The value of \(\dfrac{96 \div 16 \text{ of } 2 - 128 \times 2 \div 32 + 15 \text{ of } 4}{\dfrac{5}{6} \text{ of } \dfrac{2}{3}\left(\dfrac{1}{3} - \overline{\dfrac{1}{4} - \dfrac{1}{6}}\right)}\) is: