The length of a rectangle is five times of its breadth. If the area of the rectangle is 3125 cm2, then what is the length of the rectangle?
2 cos θ + sec θ - 2\(\sqrt{2}\) = 0, where θ is an acute angle. Find the value of θ.
In â–³ABC, if ∠B = 90°, AB = 21 cm and BC = 20 cm, then \(\dfrac{1+\sin A-\cos A}{1+\sin A+\cos A}\) is equal to:
\(-\dfrac{3}{5}\)
\(\dfrac{2}{5}\)
\(-\dfrac{2}{5}\)
\(\dfrac{3}{5}\)
If sec θ =\(\dfrac{65}{63}\) and θ is an acute angle, then the value of 8(cosec θ - cot θ) is:
If \(\dfrac{ \mathrm{cosec}\theta + \cot\theta}{ \mathrm{cosec}\theta - \cot\theta}\) = 7, then the value of \(\dfrac{4\sin^{2}\theta + 5}{4\sin^{2}\theta - 1}\) is: