SSC CGL 2024-19.09.2024-3 SSC Question Paper

SSC CGL 2024-19.09.2024-3 SSC Questions

61.

If \(\tan \theta = \frac{5}{8}\), then find the value of \(\frac{(1 + \cos \theta)(1 - \cos \theta)}{(1 + \sin \theta)(1 - \sin \theta)}\).

A.

\(\frac{5}{64}\)

B.

\(\frac{2}{25}\)

C.

\(\frac{25}{64}\)

D.

\(\frac{64}{25}\)

ANSWER :

C.\(\frac{25}{64}\)

62.

Find the gain percentage, given that Anubha sold her scooter for Rs.23,358 gaining \(\frac{1}{6}\)th of the selling price

A.

25%

B.

35%

C.

20%

D.

30%

ANSWER :

C. 20%

63.
A thief is spotted by a policeman from a distance of 195 metres. When the policeman starts the chase, the thief also starts running. If the speed of the thief is 22 km/h and that of the policeman is 27 km/h, then how far would the thief have run (in m) before he is overtaken?
A.
825
B.
951
C.
858
D.
958
ANSWER :
C. 858
64.

For the equations ax + (a2 + 1)y = 4 and 4x + ay = a2, which of the following statements is TRUE?

A.

If \(a = 6\), then \(x = \frac{325}{28},\ y = -\frac{25}{28}\) are the solutions.

B.

If \(a = 6\), then \(x = 48,\ y = 4\) are the solutions.

C.

If \(a = -12\), then \(x = \frac{325}{28},\ y = -\frac{25}{28}\) are the solutions.

D.

If \(a = -12\), then \(x = 48,\ y = 4\) are the solutions.

ANSWER :

D. If \(a = -12\), then \(x = 48,\ y = 4\) are the solutions.

65.
A cooker is marked at ₹12,500. The dealer allows successive discounts of 6%, 6% and 4% on it. What is the net selling price of the cooker?
A.
₹10603.2
B.
₹10306
C.
₹12230
D.
₹12320.6
ANSWER :
A. ₹10603.2
66.
Pranav borrows a sum of ₹598397 at the rate of 20% per annum simple interest. At the end of the first year, he repays ₹24284 towards return of principal amount borrowed. If Pranav clears all pending dues at the end of the second year, including interest payment that accrued during the first year, how much does he pay (in ₹) at the end of the second year?
A.
812514
B.
808615
C.
818513
D.
817567
ANSWER :
B. 808615
67.

In ΔPQR, if PT is the median, then which of the following is correct?

A.

PQ2 + PR2 = PT2 + QR2

B.

PQ2 + PR2 = 2(PT2 + QT2)

C.

PQ2 + PR2 = 2(PT2 - QT2 )

D.

PQ2 + PR2 = PT2 + QT2

ANSWER :

B. PQ2 + PR2 = 2(PT2 + QT2)

68.

study the given table and answer the question that follows.
Given table shows number of candidates who appeared(both male and female) in apublic examination and a percentage of those who qualified in the examination from two states X and Z. Few values are missing in the table ( indicated by -----).You are required to fill them up according to the question.

Swipe →
Year State X State Z
Number of appeared candidates Percentage of qualified candidates Number of appeared candidates Percentage of qualified candidates
2008 480 70% ------ 70%
2009 560 75% ------ 80%
2010 ------ 60% 650 50%
2011 450 89% 720 72%
2012 790 ------ 660 ------

The number of candidates appeared from State Z increased by 100% from 2008 to 2009 together is 552, What is the number of appeared candidates from state Z in 2009? 

A.

360

B.

240

C.

480

D.

600

ANSWER :

C. 480

69.

The total surface area of a closed cube is given as 1152 cm². What is the length (in cm) of each side of the cube?

A.

9\(\sqrt{2}\)

B.

4\(\sqrt{13}\)

C.

8\(\sqrt{3}\)

D.

8\(\sqrt{2}\)

ANSWER :

C. 8\(\sqrt{3}\)

70.

If tanθ+cotθ=2, and θ is an acute angle, then the value of θ is ?

A.

30°

B.

15°

C.

60°

D.

45°

ANSWER :

D. 45°