This is an analogy-based question. We need to identify the relationship between the first pair of words ("Consolation : Grief") and then find a word that shares the same relationship with "Sedative".
C) Pain — A sedative is often used to reduce or relieve pain, anxiety, or tension. In this analogy, 'Pain' fits the relationship perfectly, as a sedative is administered to mitigate or lessen pain, similar to how consolation mitigates grief.
If the length (L cm) and breadth (B cm) of a rectangle are increased by 25%, find the difference between the areas of the old and new rectangles.
\( \frac{3LB}{2} \) cm2
\( \frac{24LB}{9} \) cm2
\( \frac{9LB}{16} \) cm2
\( \frac{16LB}{9} \) cm2
To find the difference between the areas of the old and new rectangles, we first calculate the area of the original rectangle. Then, we determine the new dimensions after a 25% increase and calculate the area of the new rectangle. Finally, we subtract the old area from the new area.
Let the original length be \(L\) cm and the original breadth be \(B\) cm.
The area of the old rectangle, \(A_{\text{old}}\), is given by:
\[ A_{\text{old}} = L \times B = LB \text{ cm}^2 \]The length and breadth are increased by 25%.
New length, \(L_{\text{new}}\):
\[ L_{\text{new}} = L + 0.25L = L(1 + 0.25) = 1.25L = \frac{5}{4}L \text{ cm} \]New breadth, \(B_{\text{new}}\):
\[ B_{\text{new}} = B + 0.25B = B(1 + 0.25) = 1.25B = \frac{5}{4}B \text{ cm} \]The area of the new rectangle, \(A_{\text{new}}\), is:
\[ A_{\text{new}} = L_{\text{new}} \times B_{\text{new}} = \left(\frac{5}{4}L\right) \times \left(\frac{5}{4}B\right) = \frac{25}{16}LB \text{ cm}^2 \]The difference between the areas is \(A_{\text{new}} - A_{\text{old}}\):
\[ \text{Difference} = A_{\text{new}} - A_{\text{old}} = \frac{25}{16}LB - LB \]\[ \text{Difference} = LB \left(\frac{25}{16} - 1\right) = LB \left(\frac{25 - 16}{16}\right) = \frac{9}{16}LB \text{ cm}^2 \]C) \( \frac{9LB}{16} \) cm\(^2\) is the correct answer, as calculated above.
The question asks about the technology developed during World War II specifically for tracking enemy submarines. This requires knowledge of the historical context and the primary applications of various detection technologies.
Correct Option: B) SONAR was the technology developed and widely used during World War II to detect and track enemy submarines. It works by emitting sound pulses into the water and listening for echoes reflected off objects, such as submarines.
Read the given statement carefully and answer the given question.
Statement:
A leading tennis star who faced media after failing a dope test said, 'I don't want to end my career this way. I hope I will be given another chance to play this game. I let the sport down.'
Which of the following is true according to the given statement?
He was challenging the outcome of the dope test.
He was confident that he was right and would continue to play.
He had admitted to testing positive in dope test.
The sport let him down.
The question asks to identify a true statement based on the provided quote from a tennis star who failed a dope test. We need to analyze the star's words to understand their stance and admission.
C) He had admitted to testing positive in dope test. — The phrase "I let the sport down" immediately after failing a dope test, coupled with hoping for another chance, strongly indicates an admission of guilt regarding the positive test result.
The question asks for the approximate length of the entire human digestive tract. This is a factual recall question related to human anatomy and physiology.
Correct Option: D) 9
The question asks to identify the element that is NOT alkaline. Alkalinity is a characteristic property of alkali metals and some other basic substances. We need to classify each given element as either alkaline or non-alkaline based on its chemical properties and position in the periodic table.
Correct Option: D) Sulphur is a non-metal and forms acidic oxides, thus it is not alkaline.
To find the average age of the family, we need to calculate the total age of all family members and then divide it by the total number of family members. We are given the average ages of parents and children separately, which allows us to find their respective total ages.
Correct Option: B) 19 years
A statement followed by some conclusions is given below.
Statement:
After landing on the moon, Neil Armstrong said 'One small step for a man, a giant leap for mankind.'
Conclusions:
I. Neil Armstrong calls himself as mankind.
II. Neil Armstrong only echoed the feeling of achievement by mankind.
Find which of the given conclusions logically follow from the given statement.
Only conclusion I follows.
Only conclusion II follows.
Both I and II follow.
Neither I nor II follows.
The problem requires us to analyze a famous statement made by Neil Armstrong and determine which of the given conclusions logically follow from it. We need to evaluate each conclusion based on the literal and implied meaning of the statement.
B) Only conclusion II follows.
To calculate the percentage score, we need to find the total marks obtained by the student and the total maximum marks possible. Then, we use the formula: \[\text{Percentage} = \frac{\text{Marks Obtained}}{\text{Total Maximum Marks}} \times 100\].
The student scored 470 marks.
\[ \text{Marks Obtained} = 470 \]
There are 6 subjects, and the maximum marks for each subject is 100.
\[ \text{Total Maximum Marks} = \text{Number of Subjects} \times \text{Maximum Marks per Subject} \]
\[ \text{Total Maximum Marks} = 6 \times 100 = 600 \]
Now, use the percentage formula:
\[ \text{Percentage Score} = \frac{\text{Marks Obtained}}{\text{Total Maximum Marks}} \times 100 \]
\[ \text{Percentage Score} = \frac{470}{600} \times 100 \]
\[ \text{Percentage Score} = \frac{47}{60} \times 100 \]
\[ \text{Percentage Score} = \frac{47}{6} \times 10 \]
\[ \text{Percentage Score} = 7.8333... \times 10 \]
\[ \text{Percentage Score} = 78.333... \%\]
Rounding to two decimal places, the percentage score is 78.33%.
Correct Option: C) 78.33%
To solve this problem, we first need to find the marked price (MP) of the article using the given selling price and the initial discount percentage. Once the marked price is known, we can calculate the new selling price by applying the second discount percentage to the marked price.
We are given that the article was sold for Rs. 26,000 at a discount of 35%. This means the selling price (SP) is 65% of the marked price (MP).
\[ \text{SP} = \text{MP} - (\text{Discount Percentage} \times \text{MP}) \]\[ \text{SP} = \text{MP} (1 - \text{Discount Percentage}) \]\[ 26000 = \text{MP} (1 - 0.35) \]\[ 26000 = \text{MP} (0.65) \]\[ \text{MP} = \frac{26000}{0.65} \]\[ \text{MP} = \frac{26000}{\frac{65}{100}} \]\[ \text{MP} = \frac{26000 \times 100}{65} \]\[ \text{MP} = \frac{2600000}{65} \]\[ \text{MP} = 40000 \]Now that we have the marked price (MP = Rs. 40,000), we need to find the selling price if the discount was 15%.
\[ \text{New SP} = \text{MP} - (\text{New Discount Percentage} \times \text{MP}) \]\[ \text{New SP} = \text{MP} (1 - \text{New Discount Percentage}) \]\[ \text{New SP} = 40000 (1 - 0.15) \]\[ \text{New SP} = 40000 (0.85) \]\[ \text{New SP} = 34000 \]D) Rs. 34,000 — The marked price is Rs. 40,000. Applying a 15% discount on this marked price gives a selling price of Rs. 34,000.