The question asks to identify which of the given options is NOT a greenhouse gas. To answer this, we need to recall the definition of greenhouse gases and their common examples.
D) Oxygen — Oxygen is a diatomic molecule (\(\text{O}_2\)) that does not absorb infrared radiation effectively, and thus does not contribute to the greenhouse effect. It is not considered a greenhouse gas.
The question asks about the primary composition of stars. This is a fundamental concept in astrophysics. Stars are massive celestial bodies that produce light and heat through nuclear fusion. Understanding their composition is key to understanding their energy generation process.
Therefore, hydrogen and helium are the primary constituents of stars.
C) Hydrogen and Helium — Stars are primarily composed of hydrogen (about 75% by mass) and helium (about 24% by mass). These are the raw materials for the nuclear fusion processes that power stars.
On which date was the partition of India announced?
15th Aug 1947
3rd June 1947
17th July 1947
1st July 1947
The question asks for the specific date on which the partition of India was officially announced. This requires knowledge of key historical events and dates related to India's independence and partition.
Correct Option: B) 3rd June 1947
The partition of India, as part of the Mountbatten Plan, was officially announced on 3rd June 1947. This plan proposed the division of British India into two independent dominions, India and Pakistan, and the transfer of power by 15th August 1947.
The problem asks for the simple interest on a principal amount for a given period and rate. The key is to correctly interpret the interest rate, which is given in "paise per rupee per month". We need to convert this rate into a percentage per month to use the standard simple interest formula.
10 paise per rupee means 10 paise for every 100 paise (since 1 rupee = 100 paise). So, the rate is 10 parts out of 100 parts, which is 10%.
\[ \text{Rate (R)} = \frac{10 \text{ paise}}{1 \text{ rupee}} \times 100\% \text{ per month} \]\[ \text{Rate (R)} = \frac{10 \text{ paise}}{100 \text{ paise}} \times 100\% \text{ per month} \]\[ \text{Rate (R)} = 0.10 \times 100\% \text{ per month} \]\[ \text{Rate (R)} = 10\% \text{ per month} \]The formula for simple interest (SI) is:
\[ \text{SI} = \frac{\text{P} \times \text{R} \times \text{T}}{100} \]Here, P = 50, R = 10 (as a percentage), and T = 6 (months). Since the rate is per month and the time is in months, we can directly use these values.
\[ \text{SI} = \frac{50 \times 10 \times 6}{100} \]Therefore, the simple interest is Rs. 30.
D) Rs. 30 is the correct simple interest calculated based on the given principal, rate, and time.
We are given the initial ratio of two numbers and their ratio after a constant value is added to each. We can represent the numbers using a variable and form an equation based on the given information. Solving this equation will give us the value of the variable, which can then be used to find the actual numbers.
C) 15 & 18
The problem requires us to apply given interchanges to signs and numbers in mathematical expressions and then evaluate each option to find the correct one. The interchanges are: '+' becomes '÷', '÷' becomes '+', '2' becomes '4', and '4' becomes '2'. We will apply these rules to each option and use the order of operations (BODMAS/PEMDAS) to evaluate the resulting expression.
Let's apply the interchanges to option B: \(2 + 4 \div 6 = 8\)
After interchanges:
The expression becomes: \(4 \div 2 + 6 = 8\)
Now, evaluate the left-hand side:
\[ 4 \div 2 + 6 = 2 + 6 = 8 \]Since \(8 = 8\), option B is correct.
Applying interchanges:
\[ 2 \div 4 + 6 = 0.5 + 6 = 6.5 \]Since \(6.5 \neq 1.5\), option A is incorrect.
Applying interchanges:
\[ 4 \div 2 + 3 = 2 + 3 = 5 \]Since \(5 = 5\), this option appears correct. However, let's recheck the question. The question asks "which one of the following would be correct?". If both B and C are correct, there might be an issue with the question or options provided. Assuming only one option is correct, let's re-evaluate carefully. In competitive exams, if multiple options seem correct, it's crucial to re-verify the question and your calculations. Let's assume there is only one correct answer and proceed with the most straightforward interpretation. In this case, both B and C evaluate to true after the interchanges. However, typically in such questions, only one option is intended to be correct. Given the provided correct answer is B, let's double-check if there's any subtle difference. Both B and C follow the rules. If this were an actual exam, and both B and C were mathematically correct after substitution, it would be a flawed question. For the purpose of this explanation, we will stick to the provided correct answer B. If we strictly follow the given solution, C is incorrect because the provided solution states B is correct. Let's assume there might be a typo in the question or options if both B and C are mathematically correct. But for the sake of explanation, we will treat C as incorrect based on the provided correct answer being B.
Applying interchanges:
\[ 2 + 4 \div 3 = 2 + 1.33... = 3.33... \]Since \(3.33... \neq 4\), option D is incorrect.
The question asks to identify the inventor of stainless steel. This is a factual recall question related to scientific discoveries and inventions.
Stainless steel was invented by Harry Brearley in 1913. He discovered that adding chromium to steel made it resistant to rust and corrosion, leading to the development of what is now known as stainless steel.
Correct Option: C) Harry Brearley
This is a coding-decoding question where each letter in the word "BORDER" is assigned a specific digit. We need to identify the pattern or mapping between letters and digits and then apply the same mapping to find the code for "ORDER".
The word BORDER is coded as 579649.
Notice that the letter 'R' appears twice in BORDER and is consistently coded as 9. This confirms a direct letter-to-digit mapping.
The target word is ORDER.
Putting these digits together, ORDER is coded as 79649.
B) 79649 is the correct code for ORDER based on the established letter-to-digit mapping.
The question asks to identify the organ affected by cirrhosis. This requires knowledge of common medical conditions and their primary target organs.
B) Liver — Cirrhosis is a chronic liver disease characterized by the replacement of normal liver tissue with scar tissue, leading to impaired liver function.
The ratio between the speeds of two buses is 11:9. If the second bus runs 270 km in 15 hours, then the speed of the first bus is?
This problem involves calculating the speed of a bus using the given distance and time, and then using a given ratio of speeds to find the speed of another bus. We will first calculate the speed of the second bus and then use the ratio to determine the speed of the first bus.
The formula for speed is:
\[ \text{Speed} = \frac{\text{Distance}}{\text{Time}} \]Given that the second bus runs 270 km in 15 hours:
\[ \text{Speed}_2 = \frac{270\ \text{km}}{15\ \text{hours}} \]Performing the division:
\[ \text{Speed}_2 = 18\ \text{km/hr} \]The ratio between the speeds of the two buses (first bus : second bus) is given as 11:9.
Let \(\text{Speed}_1\) be the speed of the first bus and \(\text{Speed}_2\) be the speed of the second bus.
\[ \frac{\text{Speed}_1}{\text{Speed}_2} = \frac{11}{9} \]We know \(\text{Speed}_2 = 18\ \text{km/hr}\). Substitute this value into the ratio equation:
\[ \frac{\text{Speed}_1}{18} = \frac{11}{9} \]To find \(\text{Speed}_1\), multiply both sides by 18:
\[ \text{Speed}_1 = \frac{11}{9} \times 18 \]Simplify the expression:
\[ \text{Speed}_1 = 11 \times 2 \]\[ \text{Speed}_1 = 22\ \text{km/hr} \]
D) 22 km/hr is the correct answer, as calculated above.