The question asks to identify the first gymnast to achieve a perfect score of 10 in the Olympics. This requires knowledge of Olympic gymnastics history.
Correct Option: A) Nadia Comaneci
To find the combined weight, we first need to calculate the sister's weight. The sister's weight is 1.4 times Geetha's weight. Once we have both weights, we add them together to find the combined weight.
Geetha's weight \( = 11.235 \text{ kg}\)
The sister's weight is 1.4 times Geetha's weight.
\[ \text{Sister's weight} = 1.4 \times \text{Geetha's weight} \\ \text{Sister's weight} = 1.4 \times 11.235 \text{ kg} \\ \text{Sister's weight} = 15.729 \text{ kg} \]Combined weight is the sum of Geetha's weight and her sister's weight.
\[ \text{Combined weight} = \text{Geetha's weight} + \text{Sister's weight} \\ \text{Combined weight} = 11.235 \text{ kg} + 15.729 \text{ kg} \\ \text{Combined weight} = 26.964 \text{ kg} \]Correct Option: C) 26.964 kg.
This is a logical reasoning question based on statements and conclusions. We need to evaluate each conclusion based strictly on the information provided in the statements, without introducing outside knowledge or assumptions.
Since neither conclusion logically follows from the given statements, the correct option is B.
Correct Option: B) Neither I nor II follow
The problem requires us to determine a specific day of the week based on a sequence of events and a given reference day. We need to work backward from the known day (Friday) to find the day referred to as "tomorrow" in the conversation.
Let's represent this chronologically:
The question specifically asks for the day referred to as "tomorrow" in the conversation, which is Thursday.
B) Thursday is the correct answer because if the exams start on Friday (the day after tomorrow), then tomorrow must be Thursday.
The question asks for the specific term used to describe a deep crack in a glacier. This is a direct vocabulary question related to glaciology.
Correct Option: B) A crevasse. A crevasse is defined as a deep open crack, especially one in a glacier.
The sum of the interior angles of any quadrilateral is always 360 degrees. Given the ratio of the angles, we can represent each angle as a multiple of a common factor, sum them up, and equate them to 360 degrees to find the common factor. Once the common factor is known, we can calculate the measure of each angle, including the largest one.
Let the angles of the quadrilateral be \(3x\), \(5x\), \(9x\), and \(13x\), where \(x\) is a common factor.
The sum of the interior angles of a quadrilateral is \(360^\circ\). Therefore, we can write the equation:
\[ 3x + 5x + 9x + 13x = 360^\circ \]Combine the terms on the left side:
\[ (3 + 5 + 9 + 13)x = 360^\circ \]\[ 30x = 360^\circ \]Solve for \(x\):
\[ x = \frac{360^\circ}{30} \]\[ x = 12^\circ \]Now, calculate the measure of each angle:
Identify the largest angle among these values. The largest angle is \(156^\circ\).
Correct Option: C) 156
The question asks for the headquarters location of UNESCO. This is a factual question requiring knowledge of international organizations and their administrative centers.
Correct Option: D) Paris is the correct answer because the headquarters of UNESCO is located in Paris, France.
The question asks to identify the state to which the Madhubani painting style is native. This requires knowledge of Indian art forms and their geographical origins.
Correct Option: C) Bihar is the correct answer because Madhubani painting, also known as Mithila painting, originated in the Mithila region of Bihar.
To find the percentage of profit or loss, we need to establish a relationship between the cost price (CP) and the selling price (SP) of a single car. We are given that the cost price of 5 cars is equal to the selling price of 4 cars. We can use this information to express CP and SP in terms of a common variable or to find the ratio of SP to CP.
Set up the equation based on the given information:
Let CP be the cost price of one car and SP be the selling price of one car.
Rearrange the equation to find the ratio of SP to CP:
\[ \frac{\text{SP}}{\text{CP}} = \frac{5}{4} \]Determine if there is a profit or loss:
Since \(\text{SP} > \text{CP}\) (as \(5/4 > 1\)), there is a profit.
Calculate the profit:
\[ \text{Profit} = \text{SP} - \text{CP} \]Substitute the ratio into the profit calculation. Assume CP = 4 units and SP = 5 units for simplicity:
\[ \text{Profit} = 5 - 4 = 1 \text{ unit} \]Calculate the percentage profit:
The percentage profit is calculated as \((\text{Profit} / \text{CP}) \times 100\%).
C) 25% Profit — The calculation shows a 25% profit.
To find the smallest number to be added to the sum of squares of 15 and 14 to make it a perfect square, we first calculate the sum of the squares. Then, we find the next perfect square greater than this sum and determine the difference, which will be the number to be added.
The square of 15 is \(15^2\).
\[ 15^2 = 15 \times 15 = 225 \]The square of 14 is \(14^2\).
\[ 14^2 = 14 \times 14 = 196 \]Add the squares of 15 and 14.
\[ \text{Sum} = 225 + 196 = 421 \]We need to find the smallest perfect square that is greater than 421. Let's list squares of integers around the square root of 421:
Since \(20^2 = 400\) is less than 421, the next perfect square greater than 421 is \(21^2 = 441\).
Subtract the sum (421) from the next perfect square (441).
\[ \text{Number to be added} = 441 - 421 = 20 \]B) 20 is the smallest number that should be added to the sum of squares of 15 and 14 (which is 421) to make it a perfect square (441).