This question tests general knowledge about major sporting events. Specifically, it asks about the host nations for the Cricket World Cup 2019. Recalling the host countries for recent major tournaments is key.
Correct Option: D) England and Wales
If A means '+', @ means '×', & means '÷' and V means '–', then the value of
7 @ 2 V 135 & 5 @ 3 & 9 A 1
This problem requires us to substitute the given symbols with their corresponding mathematical operators and then evaluate the expression using the BODMAS/PEMDAS rule (Brackets, Orders/Exponents, Division, Multiplication, Addition, Subtraction).
The given expression is 7 @ 2 V 135 & 5 @ 3 & 9 A 1.
Substituting the operators, we get:
\[ 7 \times 2 - 135 \div 5 \times 3 \div 9 + 1 \]First, perform Division and Multiplication from left to right.
Step 1: Perform multiplications and divisions from left to right.
The expression becomes:
\[ 14 - 27 \times 3 \div 9 + 1 \]The expression becomes:
\[ 14 - 81 \div 9 + 1 \]The expression becomes:
\[ 14 - 9 + 1 \]The expression becomes:
\[ 5 + 1 \]C) 6 — After substituting the operators and following the BODMAS/PEMDAS rule, the value of the expression is 6.
The problem asks us to identify an alternative pair that shares the same relationship as the given pair, "Minimum : Maximum". We need to determine the nature of the relationship between "Minimum" and "Maximum" and then find the option that exhibits an identical relationship.
A) Worst : Best — "Worst" and "Best" are antonyms, representing opposite extremes of quality or desirability, similar to "Minimum" and "Maximum" which represent opposite extremes of quantity or extent.
We need to find a two-digit number based on two given conditions: the sum of its digits is 9, and the digit in the tens place is 1 more than the digit in the units place. We can solve this by setting up a system of linear equations or by testing the given options against the conditions.
C) 54 is the correct answer. The sum of its digits is \(5 + 4 = 9\), and the tens digit (5) is 1 more than the units digit (4).
The question asks for the fundamental quantities in terms of which pressure is measured. This requires recalling the definition and formula for pressure.
C) Force and Area — This option correctly identifies the two fundamental quantities (force and area) that define pressure, as per its definition and formula \(P = F/A\).
Which of the following is the least of all?
To find the least of all the given options, we need to calculate the numerical value of each option and then compare them. All calculations involve the decimal number 0.5.
The value is directly given.
\[ 0.5 \]This involves division.
\[ \frac{1}{0.5} = \frac{1}{\frac{1}{2}} = 1 \times 2 = 2 \]This involves multiplication of two decimal numbers.
\[ 0.5 \times 0.5 = 0.25 \]This involves multiplication.
\[ 0.5 \times 2 = 1 \]Now we compare the calculated values:
Arranging them in ascending order: \(0.25, 0.5, 1, 2\).
The least value among them is \(0.25\).
C) \(0.5 \times 0.5 = 0.25\). This is the smallest value among all the options.
The question asks to identify the specific instrument used for viewing the sun. This requires knowledge of various optical instruments and their specific applications.
A helioscope is a specialized telescope designed for observing the Sun. It incorporates filters and other mechanisms to reduce the intensity of sunlight to a safe level for direct viewing, protecting the observer's eyes. Standard telescopes are not safe for direct solar observation without proper solar filters.
Correct Option: C) Helioscope
To find the least number to be added to 1739 so that it is exactly divisible by 11, we can use the divisibility rule for 11 or perform long division. The divisibility rule for 11 states that a number is divisible by 11 if the difference between the sum of its digits at odd places and the sum of its digits at even places is either 0 or a multiple of 11. Alternatively, we can divide 1739 by 11 and find the remainder. The number to be added will be \(11 - \text{remainder}\).
For the number 1739:
Since 12 is not 0 or a multiple of 11, 1739 is not divisible by 11. To make it divisible by 11, the difference should be a multiple of 11. The closest multiple of 11 to 12 (and greater than or equal to 0) is 11 itself. To change the difference from 12 to 11, we need to decrease the sum of odd-placed digits by 1 or increase the sum of even-placed digits by 1. However, this rule is more complex for finding the 'number to be added'. A simpler approach is long division.
Divide 1739 by 11:
\[ \begin{array}{r} 158 \\ 11\overline{)1739} \\ -11\downarrow \\ \hline 63 \\ -55\downarrow \\ \hline 89 \\ -88 \\ \hline 1 \end{array} \]The quotient is 158 and the remainder is 1.
To make 1739 exactly divisible by 11, we need to add a number to it such that the new number has a remainder of 0 when divided by 11. Since the current remainder is 1, we need to add \(11 - 1\) to 1739.
Number to be added \( = 11 - \text{Remainder} = 11 - 1 = 10\).
Let's verify: \(1739 + 10 = 1749\). Now, divide 1749 by 11:
\[ \begin{array}{r} 159 \\ 11\overline{)1749} \\ -11\downarrow \\ \hline 64 \\ -55\downarrow \\ \hline 99 \\ -99 \\ \hline 0 \end{array} \]Since the remainder is 0, 1749 is exactly divisible by 11.
D) 10 — By dividing 1739 by 11, we get a remainder of 1. To make the number exactly divisible by 11, we need to add \(11 - 1 = 10\) to 1739.
Answer the next 3 Questions.
Comprehension:
P, W, Q, X, R, Y, Z and S sit randomly in a circle facing each other. Consider the following information and questions based on it.
1. Y sits exactly between Q and R.
2. P does not sit next to either X or Z.
3. Z is to the immediate right of Q.
4. S sits third from the left of X and the right of Y.
SubQuestion No: 1
Who sits to the left of S?
SubQuestion No: 2
If they all were facing outside the circle, W would be to the left of –
The problem describes a circular arrangement of people. We need to determine the relative position of 'W' with respect to others if everyone is facing outside the circle. We will first establish the initial seating arrangement based on the provided information (which is not explicitly given in this snippet but implied to be known from a preceding question) and then re-evaluate the left/right positions when facing outwards.
C) P — Based on the assumed arrangement and the rule for facing outside, P is immediately to the left of W when W is facing outwards.