The problem requires us to rearrange the jumbled letters in each option to form a meaningful English word. After forming the words, we need to identify the word that is different from the others based on a common category or theme.
Correct Option: C) THEA, which rearranges to HEAT, is the odd one out because HAND, HEAD, and HAIR are all parts of the human body, while HEAT is not.
This is a blood relations problem. We need to deduce the relationships between the individuals mentioned in the problem statement step-by-step to find out how Harnish is related to Karna.
Correct Option: D) Paternal Uncle
The question asks about the primary concern of the International Maritime Organisation (IMO). To answer this, one needs to recall the mandate and activities of the IMO, which is a specialized agency of the United Nations responsible for regulating shipping.
B) Sea pollution — The International Maritime Organisation (IMO) is a specialized agency of the United Nations responsible for regulating shipping. Its primary mandate includes ensuring maritime safety and security, and preventing marine and atmospheric pollution by ships. Therefore, sea pollution is a core concern of the IMO, addressed through conventions like MARPOL.
To find the Greatest Common Factor (G.C.F.) and Least Common Multiple (L.C.M.) of two numbers, we can use the prime factorization method. First, find the prime factors of each number. Then, for G.C.F., multiply the common prime factors with the lowest power. For L.C.M., multiply all prime factors (common and uncommon) with their highest power.
Correct Option: D) 4, 140
The question asks to identify the type of satellite that Astrosat is, specifically being India's first. This requires knowledge of India's space missions and their primary objectives.
C) Space observatory. Astrosat is indeed India's first dedicated multi-wavelength space observatory. It was launched by the Indian Space Research Organisation (ISRO) in 2015 and is designed to study cosmic sources in X-ray, optical, and UV spectral bands simultaneously.
To find the speed in kmph, we first need to convert the given distance and time into appropriate units (meters to kilometers, and seconds to hours) or calculate the speed in m/s and then convert it to kmph using the conversion factor.
Given time = 2 minutes and 30 seconds.
\[ \text{Time in seconds} = (2 \times 60) + 30 = 120 + 30 = 150 \text{ seconds} \]Given distance = 300 m.
\[ \text{Speed} = \frac{\text{Distance}}{\text{Time}} = \frac{300 \text{ m}}{150 \text{ s}} = 2 \text{ m/s} \]To convert speed from m/s to kmph, we multiply by \(\frac{18}{5}\) (since \(1 \text{ km} = 1000 \text{ m}\) and \(1 \text{ hour} = 3600 \text{ s}\), so \[1 \text{ m/s} = \frac{1/1000 \text{ km}}{1/3600 \text{ h}} = \frac{3600}{1000} \text{ kmph} = \frac{18}{5} \text{ kmph}\]).
\[ \text{Speed in kmph} = 2 \times \frac{18}{5} = \frac{36}{5} = 7.2 \text{ kmph} \]Correct Option: C) 7.2
The problem asks us to identify the odd pair out of four given pairs of words. We need to find a common relationship among three pairs and identify the one that does not follow this relationship.
Correct Option: C) Pen : Ink
The question asks for the year in which the Gandhi-Irwin Pact was signed. This is a factual question related to Indian history, specifically the Indian independence movement. Recalling the timeline of major events during this period is key to answering correctly.
Correct Option: B) 1931
The problem involves setting up an algebraic equation based on the given conditions and then solving for the unknown number. We are given a relationship between two numbers and the value of one of them.
Let the two numbers be \(x\) and \(y\).
We are given that one number is 15. Let \(x = 15\).
Let the other number be \(y\).
"The difference between two numbers" can be \( (x - y) \) or \( (y - x) \). Since the problem states "twice the difference", we should consider the absolute difference or assume a specific order. However, typically in such problems, if not specified, we can assume \(x > y\) or \(y > x\) and solve. Let's assume \(x > y\) for now, so the difference is \( (x - y) \).
"Twice the difference between two numbers" is \( 2(x - y) \).
"Their sum" is \( (x + y) \).
The condition states that "Twice the difference between two numbers is equal to their sum".
So, we have the equation:
\[ 2(x - y) = x + y \]Substitute \(x = 15\) into the equation:
\[ 2(15 - y) = 15 + y \]Distribute the 2 on the left side:
\[ 30 - 2y = 15 + y \]Add \(2y\) to both sides:
\[ 30 = 15 + y + 2y \]\[ 30 = 15 + 3y \]Subtract 15 from both sides:
\[ 30 - 15 = 3y \]\[ 15 = 3y \]Divide both sides by 3:
\[ y = \frac{15}{3} \]\[ y = 5 \]If the numbers are 15 and 5:
Difference \( = 15 - 5 = 10 \)
Twice the difference \( = 2 \times 10 = 20 \)
Sum \( = 15 + 5 = 20 \)
Since \( 20 = 20 \), the condition is satisfied.
C) 5 is the other number that satisfies the given condition.
To find the highest of three consecutive numbers whose sum is 126, we can represent the numbers algebraically. Consecutive numbers differ by 1. We can set up an equation based on their sum and then solve for the numbers.
Correct Option: C) 43