Pipe A can fill a tank in 15 hours, pipe B can fill the same tank in 27 hours and pipe C can fill the same tank in 10 hours. The time taken by them to fill the same tank if they operate together is:
8 \( \frac{10}{11} \) hours
9 \( \frac{10}{11} \) hours
4 \( \frac{10}{11} \) hours
12 \( \frac{10}{11} \) hours
Simplify: 2((\( \frac{6}{2} \))x² − 22x + 15) − 6(x² + 5x − 18).