The question asks about the pH level at which tooth decay begins. This is a common fact related to oral health and chemistry, often tested in general science sections of competitive exams. Tooth decay is primarily caused by acids produced by bacteria in the mouth, which demineralize tooth enamel.
C) 5.5 — Tooth decay, or dental caries, starts when the pH in the mouth drops below 5.5. At this acidic level, the enamel of the teeth begins to demineralize, making them vulnerable to damage.
The problem is a coding-decoding question. We need to identify the pattern used to transform "UNGIMMICKY" into "MIGNUYKCIM" and then apply the same pattern to "COMPLEXITY" to find the coded word.
Original word: UNGIMMICKY
Coded word: MIGNUYKCIM
Let's write the original word and its coded form, aligning them:
U N G I M M I C K Y
M I G N U Y K C I M
Observe that the coded word is formed by splitting the original word into two halves and then reversing each half, or by reversing the entire word and then swapping halves. Let's try reversing the entire word:
UNGIMMICKY reversed is YKCIMMINGU.
This is not MIGNUYKCIM.
Let's try splitting the word. "UNGIMMICKY" has 10 letters. The first half is "UNGIMM" and the second half is "ICKY".
Let's try splitting it into two halves of 5 letters each:
First half: UNGIM
Second half: MICKY
Now, let's reverse each half:
Reversed first half (UNGIM): MIGNU
Reversed second half (MICKY): YKCIM
Concatenating these reversed halves: MIGNU + YKCIM = MIGNUYKCIM.
This matches the given coded word. So, the pattern is: split the word into two equal halves, reverse each half, and then concatenate the reversed halves.
The word "COMPLEXITY" has 10 letters.
Split it into two equal halves of 5 letters each:
First half: COMPL
Second half: EXITY
Reversed first half (COMPL): LPMOC
Reversed second half (EXITY): YTIXE
LPMOC + YTIXE = LPMOCYTIXE
D) LPMOCYTIXE — This matches the result obtained by applying the identified coding pattern.
The question asks to identify the Director of Research and Analysis Wing (RAW) as of 2018. This requires knowledge of key appointments in Indian intelligence agencies during that specific period.
Correct Option: A) Anil Kumar Dhasmana was the Director of Research and Analysis Wing (RAW) from January 2017 to June 2019. Thus, he was the Director in 2018.
The question asks to identify the only Indian economist who had won the Nobel Prize as of 2018. This requires knowledge of Nobel laureates of Indian origin in economics and their award years.
Amartya Sen is a renowned Indian economist and philosopher. He was awarded the Nobel Memorial Prize in Economic Sciences in 1998 for his contributions to welfare economics and social choice theory. As of 2018, he was the only Indian economist to have received this prestigious award.
Abhijit Banerjee, while a Nobel laureate in Economics and of Indian origin, received his award in 2019, which is after the specified cut-off year of 2018.
B) Amartya Sen — Amartya Sen was awarded the Nobel Memorial Prize in Economic Sciences in 1998 for his work on welfare economics. This falls within the specified timeframe (as of 2018), making him the correct answer.
To find the mirror image of a clock time, we can use a simple rule: subtract the given time from 12:00 (or 11:60 if minutes are involved). This method works because a mirror horizontally flips the clock face, making the time appear to run backward from 12.
C) 2:30 is the correct mirror image of 9:30. When 9:30 is reflected in a mirror, the hour hand (pointing towards 9) will appear to point towards 3, and the minute hand (pointing towards 6) will still appear to point towards 6, thus showing 2:30.
Solve the following:
22 - (\( \frac{1}{4} \)){-5 - (-48) ÷ (-16)}
To solve this problem, we need to follow the order of operations, often remembered by the acronym BODMAS/PEMDAS (Brackets/Parentheses, Orders/Exponents, Division and Multiplication from left to right, Addition and Subtraction from left to right).
A) The step-by-step calculation leads to the result 24.
We need to determine if the given statements are sufficient to find the average daily wage of X, Y, and Z. The average daily wage is given by the total wage of X, Y, and Z divided by 3.
Let X, Y, and Z also denote their respective daily wages.
We need to find the value of \( \frac{X+Y+Z}{3} \).
Analyze Statement 1: Y's salary is half of (X+Z)
Analyze Statement 2: X and Y together earn ₹40 more than Z and Z earns ₹500
A) 2 alone is sufficient while 1 alone is insufficient
To find the difference between the place values of two digits in a number, we first need to determine the place value of each digit individually. The place value of a digit is its face value multiplied by the value of its position (ones, tens, hundreds, thousands, etc.).
Correct Option: B) 8995
This question tests the understanding of different forms of energy, specifically focusing on the energy possessed by an object due to its position or motion. We need to identify the type of energy a raised hammer has before it is allowed to fall.
D) Potential energy — A raised hammer, being at a certain height above the ground, possesses gravitational potential energy. This energy can be converted into kinetic energy when the hammer is allowed to fall, and then into work upon impact.
What will be the value of the kinetic energy (Ek) of a moving body with mass m, if its speed is doubled from v to 2v?
\( \frac{1}{2} \)Ek
4Ek
There will be no change in Ek
2Ek
To determine the change in kinetic energy when the speed of a body is doubled, we need to recall the formula for kinetic energy and then substitute the new speed into the formula to compare it with the initial kinetic energy.
The kinetic energy (\(E_k\)) of a moving body with mass \(m\) and speed \(v\) is given by the formula:
\[ E_k = \frac{1}{2}mv^2 \]Let the initial mass of the body be \(m\) and its initial speed be \(v\). The initial kinetic energy, \(E_{k1}\), is therefore:
\[ E_{k1} = \frac{1}{2}mv^2 \]The problem states that the speed is doubled from \(v\) to \(2v\). The mass \(m\) remains constant. So, the final speed is \(v' = 2v\). The final kinetic energy, \(E_{k2}\), will be:
\[ E_{k2} = \frac{1}{2}m(v')^2 = \frac{1}{2}m(2v)^2 \]Simplify the expression for \(E_{k2}\):
\[ E_{k2} = \frac{1}{2}m(4v^2) = 4 \left( \frac{1}{2}mv^2 \right) \]Substitute the expression for \(E_{k1}\) back into the equation for \(E_{k2}\):
\[ E_{k2} = 4 E_{k1} \]This shows that when the speed is doubled, the kinetic energy becomes four times its original value.
Correct Option: B) 4E k